A. Ebony and Ivory

题目连接：

http://www.codeforces.com/contest/633/problem/A

Description

Dante is engaged in a fight with “The Savior”. Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.

For every bullet that hits the shield, Ebony deals a units of damage while Ivory deals b units of damage. In order to break the shield Dante has to deal exactly c units of damage. Find out if this is possible.

Input

The first line of the input contains three integers a, b, c (1 ≤ a, b ≤ 100, 1 ≤ c ≤ 10 000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively.

Output

Print “Yes” (without quotes) if Dante can deal exactly c damage to the shield and “No” (without quotes) otherwise.

Sample Input

4 6 15

Sample Output

No

Hint

题意

给你 a,b,c

问你能够使用若干个a和若干个b，恰好组成c

题解：

暴力枚举一个，然后O(1)算另外一个就好了

代码

#include<bits/stdc++.h>
using namespace std;

int main()
{
    long long a,b,c;
    cin>>a>>b>>c;
    for(int i=0;i<=100000;i++)
    {
        long long res = c - a*i;
        if(res==0)return puts("Yes");
        if(res<0)break;
        long long p = res/b;
        if(p*b==res)
            return puts("Yes");
    }
    return puts("No");
}