[leetcode]Path Sum II @ Python

2023年2月6日 174次阅读 来源: 南郭子綦

原题地址：https://oj.leetcode.com/problems/path-sum-ii/

题意：

Given a binary tree and a sum, find all root-to-leaf paths where each path’s sum equals the given sum.

For example:

Given the below binary tree and 
sum = 22,

              5
             / \
            4   8
           /   / \
          11  13  4
         /  \    / \
        7    2  5   1

return

[
   [5,4,11,2],
   [5,8,4,5]
]

解题思路：这题需要将根到叶子的路径和为sum的路径都枚举出来。一样是使用递归。

代码：

# Definition for a  binary tree node
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    # @param root, a tree node
    # @param sum, an integer
    # @return a list of lists of integers
    def pathSum(self, root, sum):
        def dfs(root, currsum, valuelist):
            if root.left==None and root.right==None:
                if currsum==sum: res.append(valuelist)
            if root.left:
                dfs(root.left, currsum+root.left.val, valuelist+[root.left.val])
            if root.right:
                dfs(root.right, currsum+root.right.val, valuelist+[root.right.val])
        
        res=[]
        if root==None: return []
        dfs(root, root.val, [root.val])
        return res

 

    原文作者：南郭子綦
    原文地址: https://www.cnblogs.com/zuoyuan/p/3752503.html
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
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