#include <stdio.h>
#include <stdlib.h>
int SUMone(int N)
{
int iter = 0, icount = 0 , Ntemp, bitNum = 0;
Ntemp = N;
for(iter = 1; iter <= N; iter++)
{
Ntemp = iter;
while(Ntemp != 0)
{
bitNum = Ntemp % 10;
if(bitNum == 1)
{
icount++;
}
Ntemp = Ntemp / 10;
}
}
return icount;
}
//核心算法,高效的核心算法来计算f(N)
int Sumbetter(int N)
{
int icount = 0;
int highNum = 0;
int currNum = 0;
int lowNum = 0;
int ifactor = 1;
while(N / ifactor != 0)
{
highNum = N / (ifactor * 10);
currNum = (N / ifactor) % 10;
lowNum = N - (N / ifactor) * ifactor;
switch(currNum)
{
case 0:
icount = icount + highNum * ifactor;
break;
case 1:
icount = icount + highNum * ifactor + lowNum + 1;
break;
default:
icount = icount + (highNum + 1) * ifactor;
break;
}
ifactor = ifactor * 10;
}
return icount;
}
int main()
{
int testNum;
testNum = 205;
printf("the amount of the Number is %d\n",SUMone(testNum));
printf("the amount of the Number is %d",Sumbetter(testNum));
return 0;
}
编程之美-----1的个数
原文作者:ymjystu
原文地址: https://blog.csdn.net/qq_24338883/article/details/60873698
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/qq_24338883/article/details/60873698
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。