BZOJ-3595: [Scoi2014]方伯伯的Oj(Splay+线段树)

题目:http://www.lydsy.com/JudgeOnline/problem.php?id=3595

如果N比较小的话,我们可以用一个数组和一颗Splay来维护,但是这里的N可以到10^8,那么就Splay上维护的编号压缩一下,压成一个区间[l,r],如果需要对某[l,r]操作,那么就把该节点拆开,然后线段树动态建树,维护某编号对应在Splay上的位置,然后剩下的就是经典操作了。

代码(线段树节点开少了TLE了无数次。。。QaQ):

#include <cstdio>

#include <algorithm>

#include <cstring>

 

using namespace std ;

 

#define N 200000000

 

int ch ;

 

void getint( int &t ) {

    for ( ch = getchar(  ) ; ch < '0' || ch > '9' ; ch = getchar(  ) ) ;

    t = ch - '0' ;

    for ( ch = getchar(  ) ; ch >= '0' && ch <= '9' ; ch = getchar(  ) ) t = 10 * t + ch - '0' ;

}

 

#define clear( x ) memset( x , 0 , sizeof( x ) )

 

int n , m ;

 

#define L( t ) left[ t ]

#define R( t ) right[ t ]

#define T( t ) tag[ t ]

#define maxv 5001000

 

int left[ maxv ] , right[ maxv ] , tag[ maxv ] , V = 0 ;

 

void Init_sgt(  ) {

    clear( left ) , clear( right ) , clear( tag ) ;

    T( V = 1 ) = 0 ;

}

 

void pushdown( int t ) {

    if ( T( t ) ) {

        T( L( t ) ) = T( t ) , T( R( t ) ) = T( t ) ;

        T( t ) = 0 ;

    }

}

 

void change( int l , int r , int _l , int _r , int c , int t ) {

    if ( _l < _r ) {

        if ( ! L( t ) ) L( t ) = ++ V ;

        if ( ! R( t ) ) R( t ) = ++ V ;

        pushdown( t ) ;

    }

    if ( l == _l && r == _r ) {

        T( t ) = c ;

        return ;

    }

    int mid = ( _l + _r ) >> 1 ;

    if ( r <= mid ) change( l , r , _l , mid , c , L( t ) ) ; else

    if ( l > mid ) change( l , r , mid + 1 , _r , c , R( t ) ) ; else

    change( l , mid , _l , mid , c , L( t ) ) , change( mid + 1 , r , mid + 1 , _r , c , R( t ) ) ;

}

 

int query( int x , int l , int r , int t ) {

    if ( T( t ) ) return T( t ) ;

    int mid = ( l + r ) >> 1 ;

    return x <= mid ? query( x , l , mid , L( t ) ) : query( x , mid + 1 , r , R( t ) ) ;

}

 

#undef maxv

#undef L( t )

#undef R( t )

 

#define L( t ) Left[ t ]

#define R( t ) Right[ t ]

#define S( t ) Sum[ t ]

#define LL( t ) left_range[ t ]

#define RR( t ) right_range[ t ]

#define maxv 501000

#define F( t ) Father[ t ]

#define G( t ) F( F( t ) )

#define C( t ) ( t == L( F( t ) ) )

 

int Left[ maxv ] , Right[ maxv ] , Sum[ maxv ] , left_range[ maxv ] , right_range[ maxv ] , Father[ maxv ] , Vv ;

int root ;

 

void Init_splay(  ) {

    clear( Left ) , clear( Right ) , clear( Sum ) , clear( left_range ) , clear( right_range ) , clear( Father ) ;

    Vv = root = 1 , S( 1 ) = n , LL( 1 ) = 1 , RR( 1 ) = n ;

}

 

int k , u ;

bool flag ;

 

void update( int t ) {

    S( t ) = S( L( t ) ) + S( R( t ) ) + RR( t ) - LL( t ) + 1 ;

}

 

void zag( int t ) {

    k = R( t ) , u = F( t ) , flag = C( t ) ;

    update( F( R( t ) = L( k ) ) = t ) ;

    update( F( L( k ) = t ) = k ) ;

    if ( F( k ) = u ) if ( flag ) L( u ) = k ; else R( u ) = k ;

}

 

void zig( int t ) {

    k = L( t ) , u = F( t ) , flag = C( t ) ;

    update( F( L( t ) = R( k ) ) = t ) ;

    update( F( R( k ) = t ) = k ) ;

    if ( F( k ) = u ) if ( flag ) L( u ) = k ; else R( u ) = k ;

}

 

void splay( int t , int v ) {

    while ( F( t ) != v ) {

        if ( G( t ) == v ) if ( C( t ) ) zig( F( t ) ) ; else zag( F( t ) ) ; else {

            if ( C( t ) ) {

                if ( C( F( t ) ) ) zig( G( t ) ) ; zig( F( t ) ) ;

            } else {

                if ( ! C( F( t ) ) ) zag( G( t ) ) ; zag( F( t ) ) ;

            }

        }

    }

    if ( ! v ) root = t ;

}

 

#undef maxv

 

int ans = 0 , a , b , c , d , e ;

 

void Get( int p , int t ) {

    splay( t , 0 ) ;

    if ( LL( t ) < p ) {

        k = ++ Vv ;

        LL( k ) = LL( t ) , RR( k ) = p - 1 ;

        update( F( L( k ) = L( t ) ) = k ) ;

        update( F( L( t ) = k ) = t ) ;

        change( LL( k ) , RR( k ) , 1 , N , k , 1 ) ;

    }

    if ( RR( t ) > p ) {

        k = ++ Vv ;

        LL( k ) = p + 1 , RR( k ) = RR( t ) ;

        update( F( R( k ) = R( t ) ) = k ) ;

        update( F( R( t ) = k ) = t ) ;

        change( LL( k ) , RR( k ) , 1 , N , k , 1 ) ;

    }

    LL( t ) = RR( t ) = p ;

}

 

int Max( int t ) {

    for ( ; R( t ) ; t = R( t ) ) ;

    return t ;

}

 

int Min( int t ) {

    for ( ; L( t ) ; t = L( t  ) ) ;

    return t ;

}

 

int Select( int s ) {

    int t ;

    for ( t = root ; ; ) {

        if ( s >= S( L( t ) ) && s - S( L( t ) ) < RR( t ) - LL( t ) + 1 ) {

            s -= S( L( t ) ) ;

            break ;

        }

        if ( s < S( L( t ) ) ) t = L( t ) ; else {

            s -= ( S( L( t ) ) + RR( t ) - LL( t ) + 1 ) ;

            t = R( t ) ;

        }

    }

    splay( t , 0 ) ;

    return LL( t ) + s ;

}

 

int main(  ) {

    getint( n ) , getint( m ) ;

    Init_sgt(  ) , Init_splay(  ) ;

    change( 1 , n , 1 , N , 1 , 1 ) ;

    while ( m -- ) {

        getint( a ) , getint( b ) ;

        b -= ans ;

        if ( a == 1 ) {

            getint( c ) ;

            c -= ans ;

            d = query( b , 1 , N , 1 ) ;

            Get( b , d ) ;

            printf( "%d\n" , ans = S( L( d ) ) + 1 ) ;

            change( b , b , 1 , N , 0 , 1 ) ;

            change( c , c , 1 , N , d , 1 ) ;

            LL( d ) = RR( d ) = c ;

        } else if ( a == 2 ) {

            c = query( b , 1 , N , 1 ) ;

            Get( b , c ) ;

            printf( "%d\n" , ans = S( L( c ) ) + 1 ) ;

            if ( L( c ) ) {

                splay( d = Max( L( c ) ) , c ) ;

                update( F( R( d ) = R( c ) ) = d ) ;

                L( c ) = 0 , update( F( R( c ) = d ) = c ) ;

            }

        } else if ( a == 3 ) {

            c = query( b , 1 , N , 1 ) ;

            Get( b , c ) ;

            printf( "%d\n" , ans = S( L( c ) ) + 1 ) ;

            if ( R( c ) ) {

                splay( d = Min( R( c ) ) , c ) ;

                update( F( L( d ) = L( c ) ) = d ) ;

                R( c ) = 0 , update( F( L( c ) = d ) = c ) ;

            }

        } else {

            printf( "%d\n" , ans = Select( b - 1 ) ) ;

        }

    }

    return 0 ;

}
    原文作者:AmadeusChan
    原文地址: https://www.jianshu.com/p/5146e2df9821#comments
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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