Leetcode - Power of Two

2023年11月17日 129次阅读 来源: Richardo92

傻逼题目。不用多想。

public class Solution {
    public boolean isPowerOfTwo(int n) {
        if (n <= 0)
            return false;
        boolean ret = false;
        for (int i = 0; i < 32; i++) {
            if ((n & 0x0001) == 1) {
                if (!ret)
                    ret = true;
                else {
                    ret = false;
                    break;
                }
            }
            n = (n >> 1);
        }
        return ret;
    }
}

**
总结： bit manipulation
刷了两道简单题，神清气爽！
**

Anyway, Good luck, Richardo!

My code:

public class Solution {
    public boolean isPowerOfTwo(int n) {
        if (n < 0) {
            return false;
        }
        
        int c = 0;
        int base = 1;
        for (int i = 0; i < 32; i++) {
            if ((n & base) != 0) {
                c++;
                if (c > 1) {
                    return false;
                }
            }
            base <<= 1;
        }
        
        return c == 1;
    }
}

这道题目并不难。

Anyway, Good luck, Richardo! — 10/12/2016

My code:

public class Solution {
    public boolean isPowerOfTwo(int n) {
        return n > 0 && Math.pow(2, (int) (Math.log(Integer.MAX_VALUE) / Math.log(2))) % n == 0;
    }
}

受 power of three 启发。

Anyway, Good luck, Richardo! — 10/14/2016

    原文作者：Richardo92
    原文地址: https://www.jianshu.com/p/7c170f2a5e0f#comments
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
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