Go语言数据结构和算法-LinkedList(链表)

Go语言数据结构和算法-LinkedList(链表)

Prepend(item)       //  在链表头新增一个元素
Append(item)        //  在链表尾追加一个元素
InsertAt(i,item)    //  在索引i处插入一个元素
RemoveAt(i)         //  删除再索引i处的一个元素
Remove(item)        //  删除item元素
IndexOf(item)       //  返回item的索引
IsEmpty()           //  链表是否为空
Size()              //  链表的大小
Head()              //  链表的头节点
Tail()              //  链表的尾节点
String()            //  遍历链表

节点和链表数据结构

type Node struct {
    item interface{}
    next *Node
}

type LinkedList struct {
    head *Node
    size int
  lock sync.RWMutex
}

Prepend(item) 在链表头新增一个元素

func (list *LinkedList) Prepend(item interface{}) {
  list.lock.Lock()
    defer list.lock.Unlock()
    node := &Node{item,nil}
    if list.head == nil{
        list.head = node
    }else{
        node.next = list.head
        list.head = node
    }
    list.size += 1
}

Append(item) 在链表尾追加一个元素

func (list *LinkedList) Append(item interface{}) {
  list.lock.Lock()
    defer list.lock.Unlock()
    node := &Node{item, nil}
    if list.head == nil {
        list.head = node
    } else {
        cur := list.head
        for cur.next != nil {
            cur = cur.next
        }
        cur.next = node
    }
    list.size += 1
}

InsertAt(i,item) 在索引i处插入一个元素

func (list *LinkedList) InsertAt(i int, item interface{}) error {
    list.lock.Lock()
    defer list.lock.Unlock()
    if i > list.size || i < 0 {
        return fmt.Errorf("index error")
    }

    node := &Node{item, nil}
    if i == 0 {
        node.next = list.head
        list.head = node
        list.size += 1
        return nil
    }
    cur := list.head
    for cur.next != nil && i != 1 {
        i -= 1
        cur = cur.next
    }
    node.next = cur.next
    cur.next = node
    list.size += 1

    return nil
}

RemoveAt(i) 删除再索引i处的一个元素

func (list *LinkedList) RemoveAt(i int) bool {
    list.lock.Lock()
    defer list.lock.Unlock()
    if i < 0 || i >= list.size {
        return false
    }
    if list.head == nil {
        return false
    }

    if i == 0 {
        list.head = list.head.next
        list.size -= 1
        return true
    }

    cur := list.head
    for cur.next != nil && i != 1 {
        i -= 1
        cur = cur.next
    }
    cur.next = cur.next.next
    list.size -= 1
    return true
}

Remove(item) 删除item元素

func (list *LinkedList) Remove(item interface{}) bool {
    list.lock.Lock()
    defer list.lock.Unlock()
    if list.head == nil {
        return false
    }
    if list.head.item == item {
        list.head = list.head.next
        list.size -= 1
        return true
    }

    cur := list.head
    for cur.next != nil {
        if cur.next.item == item {
            cur.next = cur.next.next
            list.size -= 1
            return true
        }
        cur = cur.next
    }
    return false
}

IndexOf(item) 返回item的索引,如果不存在就返回-1

func (list *LinkedList) IndexOf(item interface{}) int {
  list.lock.Lock()
    defer list.lock.Unlock()
    cur := list.head
    index := -1
    for cur != nil {
        index += 1
        if item == cur.item {
            return index
        }
        cur = cur.next
    }
    return -1
}

IsEmpty() 链表是否为空

func (list *LinkedList) IsEmpty() bool {
  list.lock.Lock()
    defer list.lock.Unlock()
    return list.size == 0
}

Size() 链表的大小

func (list *LinkedList) Size() int {
  list.lock.Lock()
    defer list.lock.Unlock()
    return list.size
}

Head() 链表头节点

func (list *LinkedList) Head() *Node {
  list.lock.Lock()
    defer list.lock.Unlock()
    return list.head
}

Tail() 链表尾节点

func (list *LinkedList) Tail() *Node {
  list.lock.Lock()
    defer list.lock.Unlock()
    cur := list.head
    for cur.next != nil {
        cur = cur.next
    }
    return cur
}

String() 遍历真个链表

func (list *LinkedList) String() {
  list.lock.Lock()
    defer list.lock.Unlock()
    cur := list.head
    for cur != nil {
        fmt.Print(cur.item, "->")
        cur = cur.next
    }
}

源码

    原文作者:CoderMiner
    原文地址: https://www.jianshu.com/p/21979f91e038
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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