[LeetCode By Go 45]237. Delete Node in a Linked List

这道题目不能用go语言写答案,所以用了C语言

题目

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

解题思路

删除链表的一个节点本来需要知道该节点的前一个节点,该题目要求的函数要求只知道要删除的节点来做删除
不能删本节点,可以删下一个节点,将下个节点的值赋值给此节点,删除下个节点就行了

代码

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
void deleteNode(struct ListNode* node) {
    if (NULL == node) {
        return;
    }
    
    node->val = node->next->val;
    node->next = node->next->next;
}
    原文作者:miltonsun
    原文地址: https://www.jianshu.com/p/3843a8a0c61d
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