LeetCode 182. Duplicate Emails

2019年4月20日 181次阅读 来源: 卡尔是正太

LeetCode 182. Duplicate Emails

题目

Write a SQL query to find all duplicate emails in a table named Person.

+----+---------+
| Id | Email   |
+----+---------+
| 1  | a@b.com |
| 2  | c@d.com |
| 3  | a@b.com |
+----+---------+

For example, your query should return the following for the above table:

+---------+
| Email   |
+---------+
| a@b.com |
+---------+

Note: All emails are in lowercase.

题目大意:编写一个SQL查询从Person表中找出所有重复的邮箱地址。

解题思路

  • GROUP BY HAVING
 SELECT `Email` FROM `Person` GROUP BY `Email` HAVING COUNT(*) > 1 ```

* 做笛卡尔积

  * DISTINCT
```SQL
 SELECT DISTINCT t1.`Email`  FROM `Person` AS t1, `Person` AS  t2   WHERE t1.id != t2.id and t1.`Email` = t2.`Email` ```

  * INNER JOIN

SQL
SELECT DISTINCT p.Email FROM Person p INNER JOIN Person q ON p.Id != q.Id AND p.Email = q.Email;


*测试下来使用group by 会更快一点*

## GROUP BY HAVING 官方文档 

[GROUP BY](https://dev.mysql.com/doc/refman/5.7/en/group-by-functions.html) 数据分组(聚合)
[HAVING](https://dev.mysql.com/doc/refman/5.7/en/group-by-modifiers.html) 数据聚合后的筛选
    原文作者：卡尔是正太
    原文地址: https://www.jianshu.com/p/c65178a751ae
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
点赞