POJ 4127: 迷宫问题 BFS

代码很简单,学会使用BFS可以很快解决此类问题

#include
#include

const int maxn = 65536;
int c[4][2] = {0,1,1,0,0,-1,-1,0};
int visit[5][5];

int m[5][5];

int pre[maxn];
int q[maxn][2];

int bfs() {
    int head = 0;
    int tail = head+1;

    q[head][0] = 0;
    q[head][1] = 0;
    pre[head] = -1;
    while(head < tail) {
        if(q[head][0] == 4 && q[head][1] == 4) {
            return head;
        }

        for(int i = 0;i < 4;i++) {
            int a = q[head][0] + c[i][0];
            int b = q[head][1] + c[i][1];


            if(a >= 0 && b>= 0 && a < 5 && b < 5 && m[a][b] == 0 && visit[a][b] == 0) {
                visit[a][b] = 1;
                q[tail][0] = a;
                q[tail][1] = b;
                pre[tail] = head;
                tail++;
            }
        }

        head++;

    }

    return -1;
}

int main() {
    memset(visit,0,sizeof(visit));
    memset(m,0,sizeof(m));
    memset(q,0,sizeof(q));

    for(int i = 0;i < 5;i++) {
        for(int j = 0;j < 5;j++) {
            scanf("%d",&m[i][j]);
        }
    }

    int rslt = bfs();
    if(rslt == -1) {
        printf("No way");
    } else {
        int arr[25][2];

        int pos = 0;
        while(pre[rslt] != -1) {
            arr[pos][0] = q[rslt][0];
            arr[pos][1] = q[rslt][1];

            pos++;
            rslt = pre[rslt];
        }

        if(pre[rslt] == -1) {
            arr[pos][0] = q[rslt][0];
            arr[pos][1] = q[rslt][1];

            pos++;
        }

        for(int k = pos-1;k >= 0;k--) {
            printf("(%d, %d)\n",arr[k][0],arr[k][1]);
        }

    }

    return 0;
}
/*
0 1 0 0 0
0 1 0 1 0
0 0 0 0 0
0 1 1 1 0
0 0 0 1 0
*/
    原文作者:迷宫问题
    原文地址: https://blog.csdn.net/luoronghuaxidian/article/details/52415463
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