栈和队列_迷宫问题_递归

#迷宫问题---栈和队列  #定义maze line_0 = [1,1,1,1,1,1,1]
line_1 = [1,1,0,1,1,1,1]
line_2 = [1,1,0,1,1,1,1]
line_3 = [1,1,0,0,0,1,1]
line_4 = [1,1,0,1,0,0,1]
line_5 = [1,1,0,1,1,1,1]
line_6 = [1,1,1,1,1,1,1]
maze=[line_1,line_1,line_2,line_3,line_4,line_5,line_6]
#方向 dirs = [(0,1),(1,0),(0,-1),(-1,0)]
def mark(maze,pos):
    #定义到过了=2 maze是迷宫殿  maze[pos[0]][pos[1]]  = 2
def passable (maze,pos):
    return maze[pos[0]][pos[1]] == 0

#递归 def find_path(maze,pos,end):
    mark(maze,pos)
    if pos == end:
        return True  else:
        for i in range(4):
            nextp = pos[0]+dirs[i][0],pos[1]+dirs[i][1]
        #下一方向  if passable(maze,nextp):
                find_path(maze,nextp,end)
                print (nextp)
                return True   return False find_path(maze,[5,2],[4,5])
print (maze)
    原文作者:迷宫问题
    原文地址: https://blog.csdn.net/up_stairs/article/details/53970291
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