约瑟夫问题---单向循环链表

include

using namespace std;

define N 41

define M 3

struct node{
int value;
struct node * next;
};
typedef struct node* Node;

bool initNode(Node *head);
bool insert_tail(Node head, int value);
void print(Node head);

int main()
{
Node head = nullptr;
initNode(&head);
for (int i = 1; i <= N; i++)
{
insert_tail(head, i);
}
print(head);

int remain = N;
int count = 0;//计数器
//while (head != head->next)
Node temp = head;
while (remain >= M)
{
    if (temp->next->value != 0)//0表示淘汰出局
    {
        count++;
        if (count >= M)
        {
            count = 0;
            remain -= 1;
            temp->next->value = 0;
        }
    }
    temp = temp->next;
    if (temp->next == head)//使链表重复遍历
    {
        temp = head;
    }
}
cout << "最终编号不为0胜出" << endl;
print(head);
system("pause");

}

bool initNode(Node *head)
{
Node newnode = (Node)malloc(sizeof(struct node));
if (NULL == newnode)
{
return false;
}
newnode->next = newnode;
*head = newnode;
}

bool insert_tail(Node head, int value)
{
Node temp = head;//固定头结点位置,利用temp去遍历链表
Node newnode = (Node)malloc(sizeof(struct node));
if (NULL == newnode)
{
return false;
}
newnode->value = value;
newnode->next = head;
while (temp->next != head)//temp遍历到链表的尾
{
temp = temp->next;
}
temp->next = newnode;
return true;
}

void print(Node head)
{
Node temp = head;
while (temp->next != head)
{
cout << temp->next->value<<” “;
temp = temp->next;
}
cout << endl;
}

    原文作者:约瑟夫环问题
    原文地址: https://blog.csdn.net/qq_38374716/article/details/79243922
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