class TreeNode:
'''二叉搜索树节点的定义'''
def __init__(self, val):
self.val = val
self.left = None
self.right = None
class OperationTree:
'''二叉搜索树操作'''
def insert(self, root, val):
'''二叉搜索树插入操作'''
if root == None:
root = TreeNode(val)
elif val < root.val:
root.left = self.insert(root.left, val)
elif val > root.val:
root.right = self.insert(root.right, val)
return root
def query(self, root, val):
'''二叉搜索树查询操作'''
if root == None:
return False
if root.val == val:
return True
elif val < root.val:
return self.query(root.left, val)
elif val > root.val:
return self.query(root.right, val)
def findMin(self, root):
'''查找二叉搜索树中最小值点'''
if root.left:
return self.findMin(root.left)
else:
return root
def findMax(self, root):
'''查找二叉搜索树中最大值点'''
if root.right:
return self.findMax(root.right)
else:
return root
def delNode(self, root, val):
'''删除二叉搜索树中值为val的点'''
if root == None:
return
if val < root.val:
root.left = self.delNode(root.left, val)
elif val > root.val:
root.right = self.delNode(root.right, val)
# 当val == root.val时,分为三种情况:只有左子树或者只有右子树、有左右子树、即无左子树又无右子树
else:
if root.left and root.right:
# 既有左子树又有右子树,则需找到右子树中最小值节点
temp = self.findMin(root.right)
root.val = temp.val
# 再把右子树中最小值节点删除
root.right = self.delNode(root.right, temp.val)
elif root.right == None and root.left == None:
# 左右子树都为空
root = None
elif root.right == None:
# 只有左子树
root = root.left
elif root.left == None:
# 只有右子树
root = root.right
return root
def printTree(self, root):
# 打印二叉搜索树(中序打印,有序数列)
if root == None:
return
self.printTree(root.left)
print(root.val, end = ' ')
self.printTree(root.right)
if __name__ == '__main__':
List = [17,5,35,2,11,29,38,9,16,8]
root = None
op = OperationTree()
for val in List:
root = op.insert(root,val)
print('中序打印二叉搜索树:', end = ' ')
op.printTree(root)
print('')
print('根节点的值为:', root.val)
print('树中最大值为:', op.findMax(root).val)
print('树中最小值为:', op.findMin(root).val)
print('查询树中值为5的节点:', op.query(root, 5))
print('查询树中值为100的节点:', op.query(root, 100))
print('删除树中值为16的节点:', end = ' ')
root = op.delNode(root, 16)
op.printTree(root)
print('')
print('删除树中值为5的节点:', end = ' ')
root = op.delNode(root, 5)
op.printTree(root)
print('')
用python写二叉搜索树(BST)
原文作者:康曼德
原文地址: https://blog.csdn.net/king520089/article/details/123731685
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/king520089/article/details/123731685
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。