1. Oracle去重,group by 筛选
1. 先group by找到每个人最新的数据插入时间(insert_time)
SELECT
T.u_name,
MAX( T.insert_time ) AS t_inserttime
FROM
user_test T
GROUP BY
T.u_name
2. 通过insert_time作为条件表关联的条件筛选出每个人最新的数据
SELECT
T1.id,
T1.u_name,
T1.u_sex,
T1.u_phone,
T1.insert_time,
T1.update_by
FROM
`user_test` T1,
( SELECT T2.u_name, MAX( T2.insert_time ) AS t_inserttime FROM user_test T2 GROUP BY T2.u_name ) T3
WHERE
T1.u_name = T3.u_name
AND T1.insert_time = T3.t_inserttime
解法2:通过row_number()over()函数解决 (适用于Oracle)
row_number() over()函数的主要功能是分组排序,实现类似group by + order by的效果
SELECT
FI.*
FROM
( SELECT T.*, ROW_NUMBER ( ) OVER ( PARTITION BY T.u_name ORDER BY T.insert_time DESC ) RW FROM user_test T ) FI
WHERE
FI.RW =1
这里partition by实现了根据用户名进行分组,order by对结果集根据插入时间进行排序,row_number()函数将每一组的行数单独标注了出来。最后我们取rw=1的数据,也就取到了每个重复用户数据的最新一条数据
2更灵活,适合处理复杂筛选