Link:http://acm.hdu.edu.cn/showproblem.php?pid=2051
Bitset
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 14434 Accepted Submission(s): 10985
Problem Description Give you a number on base ten,you should output it on base two.(0 < n < 1000)
Input For each case there is a postive number n on base ten, end of file.
Output For each case output a number on base two.
Sample Input
1 2 3
Sample Output
1 10 11
Author 8600 && xhd
Source
校庆杯Warm Up
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AC code:
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cstdio>
#include<queue>
#include<cmath>
using namespace std;
int main()
{
int n,a[111],cnt,i;
while(scanf("%d",&n)!=EOF)
{
cnt=0;
while(n)
{
a[cnt++]=n%2;
n/=2;
}
for(i=cnt-1;i>=0;i--)
{
printf("%d",a[i]);
}
printf("\n");
}
}