[LeetCode] Remove Linked List Elements 移除链表元素

 

Remove all elements from a linked list of integers that have value val.

Example
Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6
Return: 1 –> 2 –> 3 –> 4 –> 5

Credits:
Special thanks to @mithmatt for adding this problem and creating all test cases.

 

这道移除链表元素是链表的基本操作之一,没有太大的难度,就是考察了基本的链表遍历和设置指针的知识点,我们只需定义几个辅助指针,然后遍历原链表,遇到与给定值相同的元素,将该元素的前后连个节点连接起来,然后删除该元素即可,要注意的是还是需要在链表开头加上一个dummy node,具体实现参见代码如下:

 

解法一:

class Solution {
public:
    ListNode* removeElements(ListNode* head, int val) {
        ListNode *dummy = new ListNode(-1), *pre = dummy;
        dummy->next = head;
        while (pre->next) {
            if (pre->next->val == val) {
                ListNode *t = pre->next;
                pre->next = t->next;
                t->next = NULL;
                delete t;
            } else {
                pre = pre->next;
            }
        }
        return dummy->next;
    }
};

 

如果只是为了通过OJ,不用写的那么严格的话,下面这种方法更加简洁,当判断下一个结点的值跟给定值相同的话,直接跳过下一个结点,将next指向下下一个结点,而根本不断开下一个结点的next,更不用删除下一个结点了。最后还要验证头结点是否需要删除,要的话直接返回下一个结点,参见代码如下:

 

解法二:

class Solution {
public:
    ListNode* removeElements(ListNode* head, int val) {
        if (!head) return NULL;
        ListNode *cur = head;
        while (cur->next) {
            if (cur->next->val == val) cur->next = cur->next->next;
            else cur = cur->next;
        }
        return head->val == val ? head->next : head;
    }
};

 

我们也可以用递归来解,写法很简洁,通过递归调用到链表末尾,然后回来,需要要删的元素,将链表next指针指向下一个元素即可:

 

解法三:

class Solution {
public:
    ListNode* removeElements(ListNode* head, int val) {
        if (!head) return NULL;
        head->next = removeElements(head->next, val);
        return head->val == val ? head->next : head;
    }
};

 

类似题目:

Remove Element

Delete Node in a Linked List

 

参考资料:

https://leetcode.com/problems/remove-linked-list-elements/

https://leetcode.com/problems/remove-linked-list-elements/discuss/57324/AC-Java-solution

https://leetcode.com/problems/remove-linked-list-elements/discuss/57306/3-line-recursive-solution

https://leetcode.com/problems/remove-linked-list-elements/discuss/57331/Accepted-7-line-clean-java-solution

 

    原文作者:Grandyang
    原文地址: http://www.cnblogs.com/grandyang/p/4452252.html
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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