Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.
Example:
Input: "babad" Output: "bab" Note: "aba" is also a valid answer.
Example:
Input: "cbbd" Output: "bb"
求最长回文字符串,容易理解,但是复杂性较高,先摘下代码,之后有改进继续更新
class Solution {
public:
string longestPalindrome(string s) {
int start=0;
int longlen=1;
int len = s.size();
if(len<=1){
return s;
}
for(int j=0;j<len-1;j++){
if(s[j]==s[j+1]){
start=j;
longlen=2;
}
}
int klen=3;
while(klen<=len){// 从长度为3开始遍历
for(int k=0;k<len-klen+1;k++){
int begin=k;int back=k+klen-1;//记录下字符串的开头和结尾
while(begin<back){
if(s[begin]!=s[back]) break;
else
begin++;
back--;
}
if(begin>=back){
start=k;
longlen=klen;
break;
}
}
klen++;
}
return s.substr(start,longlen);
}
};