前言:为了后续的实习面试,开始疯狂刷题,非常欢迎志同道合的朋友一起交流。因为时间比较紧张,目前的规划是先过一遍,写出能想到的最优算法,第二遍再考虑最优或者较优的方法。如有错误欢迎指正。博主首发CSDN,mcf171专栏。这次比赛略无语,没想到前3题都可以用暴力解。
博客链接:mcf171的博客
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Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1 / \ 2 3 / \ 4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
这个题目采用后序遍历即可。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
int maxLength = 0;
public int diameterOfBinaryTree(TreeNode root) {
help(root);
return maxLength;
}
public int help(TreeNode root){
if(root == null) return 0;
int left = help(root.left);
int right = help(root.right);
maxLength = Math.max(left + right, maxLength);
return Math.max(left + 1, right + 1);
}
}