问题描述: 给定一个长度为N的整数数组,只允许用乘法,不许用除法,求数组中任意N-1个数字的最大乘积
想法1: 计算数组中除去 a[i]以外后的其他数字的乘积,然后在其中找到最大值。 s[i] = s[i-1]*arr[i-1]; t[i] = t[i+1]*arr[i+1];
p[i] = s[i]*t[i];
代码示例中 :
calc1()
想法2: 找出程序中正数,负数和0 的个数
1 ) 如果有2个0,那么乘积一定是0 2) 如果有一个0,如果有奇数个负数,那么乘积是0 3) 如果有一个0,如果有偶数个负数,去掉0后计算乘积 4) 如果都是正数,那么去掉最小的正数 5) 如果都是正数,那么去掉最小的正数 6) 如果有奇数个负数,去掉最大的负数 7) 如果有偶数个负数,去掉最小的正数。
代码示例中 :
calc2()
#include <iostream>
using namespace std;
int calc1(int arr[], int len)
{
int *p=NULL, *s=NULL, *t=NULL;
int i = 0, max = 0, index = 0;
if (len == 0)
return 0;
p = new int[len]; s = new int[len]; t = new int[len];
s[0] = 1;
for (i = 1; i < len; i++)
{
s[i] = s[i-1]*arr[i-1];
cout << s[i] << " ";
}
cout << endl <<endl;
t[len-1] = 1;
for (i = len-2; i >= 0; i--)
{
t[i] = t[i+1]*arr[i+1];
cout << t[i] << " ";
}
cout << endl <<endl;
for (i = 0; i < len-1; i++)
{
p[i] = s[i]*t[i];
if (p[i] > max)
{
index = i;
max = p[i];
}
cout << p[i] << " ";
}
cout << endl <<endl;
cout << "Max value="<< max << " index="<< index << endl;
cout << "\n------------------"<< endl <<endl;
delete[] p; delete[] s; delete[] t;
p = NULL; s = NULL; t = NULL;
return max;
}
int calc2(int arr[], int len)
{
int i = 0, max = 1, index = 0;
int zeroCnt = 0, posCnt = 0, negCnt = 0;
int maxNegIdx = 0, minPosIdx = 0;
if (len == 0)
return 0;
for (i = 0; i < len; i++)
{
if (0 == arr[i])
{
zeroCnt++;
}
else if(arr[i] > 0)
{
posCnt++;
if (arr[i] < arr[maxNegIdx])
minPosIdx = i;
}
else
{
negCnt++;
if ((arr[maxNegIdx] > 0) || (arr[i] > arr[maxNegIdx]))
maxNegIdx = i;
}
}
if (zeroCnt > 1)
{
max = 0;
}
else if (zeroCnt == 1)
{
if (negCnt%2 == 1)
max = 0;
else
for (i = 0; i < len; i++)
if (arr[i] != 0)
max *= arr[i];
else
index = i;
}
else
{
if (negCnt%2 == 1)
for (i = 0; i < len; i++)
if (i != maxNegIdx)
max *= arr[i];
else
index = i;
else
for (i = 0; i < len; i++)
if (i != minPosIdx)
max *= arr[i];
else
index = i;
}
cout << "Max value="<< max << " index="<< index << endl;
cout << "\n------------------"<< endl <<endl;
return max;
}
int main()
{
int test[] = {3, 4, 2, 5, 6, 7, 8};
int len = sizeof(test)/sizeof(test[0]);
int test1[] = {2, 0, 4, 5, 6, 7, 8};
int len1 = sizeof(test)/sizeof(test[0]);
int test2[] ={2, 0, 4, 0, 6, 7, 8};
int len2 = sizeof(test)/sizeof(test[0]);
int test3[] = {2, 3, 4, -5, 6, 7, 8};
int len3 = sizeof(test)/sizeof(test[0]);
int test4[] = {2, 3, -4, 5, -6, 7, 8};
int len4 = sizeof(test)/sizeof(test[0]);
calc1(test, len);
calc1(test1, len1);
calc1(test2, len2);
calc1(test3, len3);
calc1(test4, len4);
cout << "\n\n============================================" << endl << endl;
calc2(test, len);
calc2(test1, len1);
calc2(test2, len2);
calc2(test3, len3);
calc2(test4, len4);
cin >> len;
return 0;
}