C++ Primer 学习中。。。
简单记录下我的学习过程 (代码为主)
adjacent_find //用来查找连续两个相等的或者符合方法的
#include<iostream>
#include<cstdio>
#include<string>
#include <vector>
#include<algorithm>
using namespace std;
/*****************************************
//所有容器适用(线性的)
adjacent_find(b,e);
adjacent_find(b,e,p);
用来查找连续两个相等的或者符合方法的
如果是已序区间
则选用已序区间查找算法
binary_search()
includes()
lower_bound()
upper_bound()
*****************************************/
/*************************************************************************************
std::adjacent_find() 所有容器适用 algorithm
--------------------------------------------------------------------------------------
template <class ForwardIterator>
ForwardIterator adjacent_find ( ForwardIterator first, ForwardIterator last );
template <class ForwardIterator, class BinaryPredicate>
ForwardIterator adjacent_find ( ForwardIterator first, ForwardIterator last,
BinaryPredicate pred );
//eg:
template <class ForwardIterator>
ForwardIterator adjacent_find ( ForwardIterator first, ForwardIterator last )
{
if (first != last)
{
ForwardIterator next=first;
++next;
while (next != last)
{
if (*first == *next) // or: if (pred(*first,*next)), for the pred version
return first;
else{++first;++next;}
}
}
return last;
}
*************************************************************************************/
bool myfunction (int i, int j)
{
return (i==j*2);
}
int main()
{
int myints[] = {10,20,30,30,40,20,10,20};
vector<int> myvector (myints,myints+8);
vector<int>::iterator it;
for(it=myvector.begin();it!=myvector.end();++it)
cout<<*it<<" ";
cout<<endl;
// using default comparison:
it = adjacent_find (myvector.begin(), myvector.end());
if (it!=myvector.end())
cout << "the first consecutive repeated elements are: " << *it << endl;
//using predicate comparison:
it = adjacent_find (myvector.begin(), myvector.end(), myfunction);
if (it!=myvector.end())
cout << "the second consecutive repeated elements are: " << *it << endl;
return 0;
}
/*****
Output
10 20 30 30 40 20 10 20
the first consecutive repeated elements are: 30
the second consecutive repeated elements are: 40
*/