如何在Android中使用Jackson从JSONArray url获取java对象

2023年7月28日 161次阅读

这是我的URL中的
JSON

https://api.myjson.com/bins/142jr

[
  {
    "serviceNo":"SR0000000001",
    "serDate":"17",
    "serMonth":"DEC",
    "serYear":"2015",
    "serTime":"02.30 AM",
    "serApartmentName":"Galaxy Apartments"
  },
  {
    "serviceNo":"SR0000000002",
    "serDate":"19",
    "serMonth":"JUN",
    "serYear":"2016",
    "serTime":"03.30 AM",
    "serApartmentName":"The Great Apartments"
  }
]

我有一个ListView我希望从在线JSON填充详细信息,上面给出了一个链接和示例json任何人给出了java中的示例jackson代码

谢谢你的进步,
Rajesh Rajendiran

最佳答案 要使用jackson,您需要创建一个模型类：

[
  {
    "serviceNo":"SR0000000001",
    "serDate":"17",
    "serMonth":"DEC",
    "serYear":"2015",
    "serTime":"02.30 AM",
    "serApartmentName":"Galaxy Apartments"
  },
  {
    "serviceNo":"SR0000000002",
    "serDate":"19",
    "serMonth":"JUN",
    "serYear":"2016",
    "serTime":"03.30 AM",
    "serApartmentName":"The Great Apartments"
  }
]

对于上面的json,模型类将是：

public class SomeClass {
 private String serviceNo;
 private String serDate;
 private String serMonth;
 private String serYear;
 private String serTime;
 private String serApartmentName;

 @JsonProperty("serviceNo") //to bind it to serviceNo attribute of the json string
 public String getServiceNo() {
  return serviceNo;
 }

 public void setServiceNo(String sNo) { //@JsonProperty need not be specified again
  serviceNo = sNo;
 }

 //create getter setters like above for all the properties.
 //if you want to avoid a key-value from getting parsed use @JsonIgnore annotation

}

现在每当你将上面的json作为存储在变量中的字符串说jsonString时,使用以下代码来解析它：

ObjectMapper mapper = new ObjectMapper(); // create once, reuse
ArrayList<SomeClass> results = mapper.readValue(jsonString,
   new TypeReference<ArrayList<ResultValue>>() { } );

结果现在应该包含两个SomeClass对象,将上面的json解析为相应的对象.

PS：自从我使用Jackson进行解析以来已经很长时间了,所以这段代码可能需要一些改进.

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