这是C#编译器完成的优化吗?

我通过lambda表达式创建了一批匿名函数.我想使用TaskId来区分匿名函数.

这是代码:

int count = 3;
int i;
for (int j = 0; j < 10; j++)
{
    i = 0;
    Func<bool, Task<int>> func = async (b) =>
    {
        return j;
    };
    while (i++ < count)
    {
        var task = func(true);
        Console.WriteLine(String.Format("Task Result:{0} TaskId:{1}",
            task.Result, task.Id));
    }
}

这是输出

Task Result:0 TaskId:1
Task Result:0 TaskId:1
Task Result:0 TaskId:1
Task Result:1 TaskId:2
Task Result:1 TaskId:2
Task Result:1 TaskId:2
Task Result:2 TaskId:3
Task Result:2 TaskId:3
Task Result:2 TaskId:3
Task Result:3 TaskId:4
Task Result:3 TaskId:4
Task Result:3 TaskId:4
Task Result:4 TaskId:5
Task Result:4 TaskId:5
Task Result:4 TaskId:5
Task Result:5 TaskId:6
Task Result:5 TaskId:6
Task Result:5 TaskId:6
Task Result:6 TaskId:7
Task Result:6 TaskId:7
Task Result:6 TaskId:7
Task Result:7 TaskId:8
Task Result:7 TaskId:8
Task Result:7 TaskId:8
Task Result:8 TaskId:9
Task Result:8 TaskId:9
Task Result:8 TaskId:9
Task Result:9 TaskId:10
Task Result:9 TaskId:11
Task Result:9 TaskId:12

如您所见,TaskId已更改,因为结果大于8.我想知道这种现象的原因.谢谢你的帮助:)

最佳答案 它本身不是编译器,而是正在进行缓存的.NET框架.查看编译器用于管理异步方法生成的状态机的
AsyncMethodBuilder代码.看起来SetResult在GetTaskForResult中做了一些缓存.有一些非常具体的代码用于缓存基本值类型,包括:

// For Int32, we cache a range of common values, e.g. [-1,4).
else if (typeof(TResult) == typeof(Int32))
{
    // Compare to constants to avoid static field access if outside of cached range.
    // We compare to the upper bound first, as we're more likely to cache miss on the upper side than on the 
    // lower side, due to positive values being more common than negative as return values.
    Int32 value = (Int32)(object)result;
    if (value < AsyncTaskCache.EXCLUSIVE_INT32_MAX &&
        value >= AsyncTaskCache.INCLUSIVE_INT32_MIN)
    {
        Task<Int32> task = AsyncTaskCache.Int32Tasks[value - AsyncTaskCache.INCLUSIVE_INT32_MIN];
        return JitHelpers.UnsafeCast<Task<TResult>>(task); // UnsafeCast avoids a type check we know will succeed
    }
}

我们看到:

/// <summary>The minimum value, inclusive, for which we want a cached task.</summary>
internal const Int32 INCLUSIVE_INT32_MIN = -1;
/// <summary>The maximum value, exclusive, for which we want a cached task.</summary>
internal const Int32 EXCLUSIVE_INT32_MAX = 9;

这就是为什么8是神奇的截止.值得注意的是-1也应该被缓存,并且从我的测试开始.

点赞