Python：到目前为止的十六进制

2024年1月19日 209次阅读 
23 DD 78 34 = 2013-01-28 21:52:XX //second not sure
92 e3 78 34 = 2013-01-28 22:14:XX 
d4 e3 78 34 = 2013-01-28 22:15:XX 
16 e4 78 34 = 2013-01-28 22:16:XX

如何将十六进制转换为日期时间？它不是UNIX Date

最佳答案 十六进制值看起来像是小端编码,但它不会使用秒作为刻度值：

>>> values = [
...    (0x3478dd23, datetime(2013, 1, 28, 21, 52)),
...    (0x3478e392, datetime(2013, 1, 28, 22, 14)),
...    (0x3478e3d4, datetime(2013, 1, 28, 22, 15)),
...    (0x3478e416, datetime(2013, 1, 28, 22, 16))
... ]
...
>>> for s, dt in values:
...     print dt - datetime.fromtimestamp(s)
... 
5544 days, 19:02:37
5544 days, 18:57:10
5544 days, 18:57:04
5544 days, 18:56:58

由于偏移量随着时间的推移而缩小,我计算出一个修正系数：

>>> ts_delta = values[1][0] - values[0][0]
>>> ts_delta
1647
>>> dt_delta = values[1][1] - values[0][1]
>>> dt_delta
datetime.timedelta(0, 1320)
>>> dt_delta = dt_delta.days * 60*60*24 + dt_delta.seconds
>>> dt_delta
1320
>>> factor = float(dt_delta) / float(ts_delta)
>>> factor
0.8014571948998178

1647滴答= 1320秒.

现在,如果我们将此因子应用于时间戳,则偏移量保持相当恒定(除了秒,但由于您不知道它们的值,我刚刚在源数据中使用了0)

>>> for s, dt in values:
...     print dt - datetime.fromtimestamp(s * factor)
... 
7567 days, 17:16:08.233151
7567 days, 17:16:08.233151
7567 days, 17:16:15.336976
7567 days, 17:16:22.440802

考虑到这一点,您可以使用此偏移量和因子来转换原始值：

>>> offset = values[0][1] - datetime.fromtimestamp(values[0][0]*factor)
>>> offset
datetime.timedelta(7567, 62168, 233151)

def hex_to_datetime(s):
    return datetime.fromtimestamp(s*factor) + offset

>>> for s, dt in values:
...     print hex_to_datetime(s), dt
... 
2013-01-28 21:52:00 2013-01-28 21:52:00
2013-01-28 22:14:00 2013-01-28 22:14:00
2013-01-28 22:14:52.896175 2013-01-28 22:15:00
2013-01-28 22:15:45.792349 2013-01-28 22:16:00

这看起来很有希望.

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