我有一个iOS应用程序,我想集成推送通知.我见过
tutorial on youtube,一切都还可以,但最近我使用的是开发证书(用于测试 – 不用于AppStore),我的服务器上有PHP脚本.在这个文件中存储了deviceToken,它有我的iPhone并且用php变量$deviceToken编写.但是现在,当我想在AppStore中使用它时,如何从已下载我的应用程序并将其加入PHP脚本的每个人那里获取设备令牌?
这是我的PHP文件:
if($_POST['message']){
$deviceToken = '(my device token)';
$message = stripslashes($_POST['message']);
$payload = '{
"aps" :
{ "alert" : "'.$message.'",
"badge" : 1,
"sound" : "bingbong.aiff"
}
}';
$ctx = stream_context_create();
stream_context_set_option($ctx, 'ssl', 'local_cert', 'cert.pem');
stream_context_set_option($ctx, 'ssl', 'passphrase', 'password');
$fp = stream_socket_client('ssl://gateway.sandbox.push.apple.com:2195', $err, $errstr, 60, STREAM_CLIENT_CONNECT, $ctx);
if(!$fp){
print "Failed to connect $err $errstrn";
return;
} else {
print "DONE!";
}
$devArray = array();
$devArray[] = $deviceToken;
foreach($devArray as $deviceToken){
$msg = chr(0) . pack("n",32) . pack('H*', str_replace(' ', '', $deviceToken)) . pack ("n",strlen($payload)) . $payload;
fwrite($fp, $msg);
}
fclose($fp);
}
<form action="send-notification.php" method="post">
<input type="text" name="message" maxlength="100">
<input type="submit" value="SEND">
</form>
</body>
这就是我在xCode(AppDelegate.m)中所拥有的
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
// Override point for customization after application launch.
[[UIApplication sharedApplication] registerForRemoteNotificationTypes:(UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge | UIRemoteNotificationTypeSound)];
return YES;
}
- (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
NSString *deviceTokenString = [NSString stringWithFormat:@"%@", deviceToken];
NSLog(deviceTokenString);
}
最佳答案 好吧,我不懂PHP,所以我不能给你具体的代码,但我可以解释一般原理.
当您的应用程序启动时,您应该通过调用registerForRemoteNotificationTypes:方法注册到Apple推送通知.
当注册成功并且您获得设备令牌时,您应该在应用程序的实现中将其发送到您的服务器:didRegisterForRemoteNotificationsWithDeviceToken:.
您的服务器应将其存储在某些数据库中.
发送通知的PHP脚本应该从该数据库获取设备令牌.