mysql – 什么可以导致连接比分为两个查询慢？

2023年3月20日 204次阅读

我正在从多个表执行JOIN以执行分面搜索.当避免JOIN并将查询分成两个不同的时候我注意到了一个很大的性能提升,所以我假设我的JOIN没有优化.

结构：

-- tags
userId  |   tagId
1              3
1              4
2              3
2              9

-- search
userId   |   number  |   countryId   |   stateId ...  
1              13           221             55

-- countries
countryId     |  countryName   
221                 Somewhere

-- users
userId    |   profileImageLink
1         |   <photo link>

我正在尝试提取所有具有标记的用户,根据search.number进行排序并从其他表中提取元数据.查询：

SELECT 
    search.*, users.a, users.b, users.c, users.d, users.e, users.f, countries.location_country, states.location_state, cities.location_city 
FROM search 
RIGHT JOIN tags 
   ON search.user_id = tags.user_id 
LEFT JOIN users 
   ON users.user_id=search.user_id 
LEFT JOIN countries 
   ON countries.countryId=search.countryId 
LEFT JOIN states 
   ON states.countryId=search.countryId AND states.stateId=search.stateId 
LEFT JOIN cities 
   ON cities.countryId=search.countryId AND cities.stateId=search.stateId AND cities.cityId=search.cityId 
WHERE 
  tags.skillId =52772 
ORDER BY 
  search.number DESC LIMIT 0,200

我注意到将JOIN删除到users表(之后这样做)使查询更快.如何优化它以在同一查询中工作？我已经尝试将FROM更改为标签而不是搜索,但这不起作用……

这是EXPLAIN显示的内容：

id  select_type table   type    possible_keys   key key_len ref rows    Extra
1   SIMPLE  tags    ref skill_user,skillId  skill_user  4   const   184854  Using index; Using temporary; Using filesort
1   SIMPLE  search  eq_ref  user_id user_id 4   tags.user_id    1   
1   SIMPLE  countries   eq_ref  PRIMARY PRIMARY 2   search.countryId    1   
1   SIMPLE  states  eq_ref  PRIMARY,state   PRIMARY 3   search.stateId  1   
1   SIMPLE  cities  eq_ref  PRIMARY,city    PRIMARY 3   search.cityId   1   
1   SIMPLE  users   eq_ref  user_id user_id 4   search.user_id  1   

EXPLAIN without the LEFT JOIN users:

id  select_type table   type    possible_keys   key key_len ref rows    Extra
1   SIMPLE  tags    ref skill_user,skillId  skill_user  4   const   155870  Using index
1   SIMPLE  search  eq_ref  user_id user_id 4   tags.user_id    1   
1   SIMPLE  countries   eq_ref  PRIMARY PRIMARY 2   search.countryId    1   
1   SIMPLE  states  eq_ref  PRIMARY,state   PRIMARY 3   search.stateId  1   
1   SIMPLE  cities  eq_ref  PRIMARY,city    PRIMARY 3   search.cityId   1

在回答中建议查询的解释：

id  select_type table   type    possible_keys   key key_len ref rows    Extra
1   SIMPLE  tags    index   NULL    userid_skill    8   NULL    22689539    Using where; Using index; Using temporary; Using filesort
1   SIMPLE  search  eq_ref  user_id user_id 4   tags.user_id    1   
1   SIMPLE  users   eq_ref  user_id user_id 4   search.user_id  1   
1   SIMPLE  countries   eq_ref  PRIMARY PRIMARY 2   search.countryId    1   
1   SIMPLE  states  eq_ref  PRIMARY,state   PRIMARY 3   search.stateId  1   
1   SIMPLE  cities  eq_ref  PRIMARY,city    PRIMARY 3   search.cityId   1

最佳答案 在表上创建索引以在查询下运行：

Table    ColumnName
------   ----------
tags     user_id, skillid (Both column in one index)

试试这个：

SELECT s.*, u.a, u.b, u.c, u.d, u.e, u.f, c.location_country, 
       st.location_state, ct.location_city 
FROM tags t 
LEFT JOIN search s ON t.user_id = s.user_id 
LEFT JOIN users u ON t.user_id = u.user_id 
LEFT JOIN countries c ON s.countryId = c.countryId 
LEFT JOIN states st ON s.stateId = st.stateId 
LEFT JOIN cities ci ON s.cityId= ct.cityId 
WHERE t.skillId =52772 
ORDER BY s.number DESC 
LIMIT 0,200

编辑

尝试使用适当的索引这两个查询,让我知道以下查询是否适合您.

SELECT s.*, u.a, u.b, u.c, u.d, u.e, u.f, c.location_country, 
       st.location_state, ct.location_city 
FROM (SELECT user_id FROM tags WHERE t.skillId = 52772) AS t 
LEFT JOIN search s ON t.user_id = s.user_id 
LEFT JOIN users u ON t.user_id = u.user_id 
LEFT JOIN countries c ON s.countryId = c.countryId 
LEFT JOIN states st ON s.stateId = st.stateId 
LEFT JOIN cities ci ON s.cityId= ct.cityId 
ORDER BY s.number DESC 
LIMIT 0,200;

要么

SELECT s.*, u.a, u.b, u.c, u.d, u.e, u.f, c.location_country, 
       st.location_state, ct.location_city 
FROM (SELECT t.user_id, s.* FROM tags t 
      LEFT JOIN search s ON t.user_id = s.user_id  
      WHERE t.skillId = 52772 
      ORDER BY s.number DESC 
      LIMIT 0,200) AS t 
LEFT JOIN users u ON t.user_id = u.user_id 
LEFT JOIN countries c ON s.countryId = c.countryId 
LEFT JOIN states st ON s.stateId = st.stateId 
LEFT JOIN cities ci ON s.cityId= ct.cityId 
ORDER BY s.number DESC 
LIMIT 0,200;
点赞