sql – 查询按每日显示分组为From-To日期

2023年2月23日 561次阅读

我的数据如下表所示

SERVICE_ID  DATE_SEQ    DAY_SEQ
101004           2012-10-18       1
101004           2012-10-19       2
101001           2012-10-20       3
101004           2012-10-21       4

我希望查询生成日期显示为范围与日期{从 – 到}它将按服务ID分组,日期是序列,如果最终它显示为
输出：

**Service_id**      **From-To**                **Date**
101004      2012-10-18 - 2012-10-19         1-2
101001      2012-10-20 - 2012-10-20         3-3
101004      2012-10-21 - 2012-10-21         4-4

最佳答案 试试这个

DECLARE @TB AS TABLE(
  SERVICE_ID INTEGER,
  DATE_SEQ SMALLDATETIME,
  DAY_SEQ NVARCHAR(10),
  FARE_SUP_ID INT
)

INSERT INTO @TB VALUES
  (101004,'2012-10-18 00:00:00',1,267),
  (101001,'2012-10-19 00:00:00',2,171),
  (101004,'2012-10-20 00:00:00',3,267),
  (101004,'2012-10-21 00:00:00',4,171),
  (101001,'2012-10-22 00:00:00',5,171),
  (101001,'2012-10-23 00:00:00',6,171),
  (101004,'2012-10-24 00:00:00',7,267)

SELECT * fROM @TB

;WITH TB1 AS (


SELECT 
  T1.SERVICE_ID,
  MIN(T1.DATE_SEQ) AS CHECK_IN, 
  MAX(T2.DATE_SEQ) AS CHECK_OUT,
  MIN (T1.DAY_SEQ) + ' - ' + MAX(T2.DAY_SEQ) AS DAY_SEQ,
  MAX(T1.FARE_SUP_ID) AS FARE_SUP_ID,
  1 AS DIFF
  FROM @TB T1 INNER JOIN @TB T2
    ON T1.SERVICE_ID = T2.SERVICE_ID
  WHERE DATEDIFF(DY, T1.DATE_SEQ ,T2.DATE_SEQ) = 1
  GROUP BY 
    T1.SERVICE_ID

UNION ALL

SELECT  T3.SERVICE_ID,T3.DATE_SEQ AS CHECK_IN ,T4.DATE_SEQ AS CHECK_OUT 
  ,T3.DAY_SEQ,T3.FARE_SUP_ID,DATEDIFF(DY, T3.DATE_SEQ ,T4.DATE_SEQ)  AS DIFF
  FROM @TB T3 INNER JOIN @TB T4
    ON T3.SERVICE_ID = T4.SERVICE_ID
  WHERE DATEDIFF(DY, T3.DATE_SEQ ,T4.DATE_SEQ) = 0
    AND 
    T3.DATE_SEQ NOT IN (
      SELECT T1.DATE_SEQ
        FROM @TB T1 INNER JOIN @TB T2
          ON T1.SERVICE_ID = T2.SERVICE_ID
        WHERE DATEDIFF(DY, T1.DATE_SEQ ,T2.DATE_SEQ) = 1
    )
    AND 
      T4.DATE_SEQ NOT IN (
        SELECT T2.DATE_SEQ
          FROM @TB T1 INNER JOIN @TB T2
            ON T1.SERVICE_ID = T2.SERVICE_ID
          WHERE DATEDIFF(DY, T1.DATE_SEQ ,T2.DATE_SEQ) = 1
      )
  )
SELECT 
  *
  FROM TB1
  ORDER BY DAY_SEQ
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