python – 多元组条件的计数器

2023年1月27日 310次阅读

我有一个元组..

for i in my_tup:
   print(i)

输出：

   (Transfer, 0:33:20, Cycle 1)                 
   (Transfer, 0:33:10, Cycle 1)                    
   (Download, 0:09:10, Cycle 1)          
   (Transfer, 0:33:10, Cycle 1)                   
   (Download, 0:13:00, Cycle 1)            
   (Download, 0:12:30, Cycle 2)           
   (Transfer, 0:33:10, Cycle 2)              
   (Download, 0:02:00, Cycle 2)            
   (Transfer, 0:33:00, Cycle 2)              
   (Transfer, 0:33:00, Cycle 2)               
   (Transfer, 0:33:00, Cycle 2)            
   (Transfer, 0:32:40, Cycle 2)

我正在尝试计算“转移”PER周期类别的出现次数.即循环1中有多少转移发生,循环2中有多少转移发生等等…

我可以在第一个周期中解决它,但不能在此之后解决这个问题.(实际输出中还有更多的周期).

accumulatedList = []
count = 0
for i in range(0 len(my_tup)):
     if my_tup[i][0] == 'Transfer' and my_tup[i][2] == 'Cycle 1':
          count +=1
     accumulatedList.append(count)

不知道如何为其他人做这件事.

最佳答案 使用pandas库很简单：

import pandas as pd
df = pd.DataFrame(my_tup, columns=['Category', 'TimeSpan', 'Cycle'])
g = df.groupby(['Category', 'Cycle']).size()

它返回：

Category  Cycle  
Download  Cycle 1    2
          Cycle 2    2
Transfer  Cycle 1    3
          Cycle 2    5
dtype: int64

如果您只关心转移,请使用索引对其进行切片：

g['Transfer']

Cycle
Cycle 1    3
Cycle 2    5
dtype: int64
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