我正在尝试更改sqlite3文件中的一些数据,而我在
python和google-fu中不存在的知识让我最终得到了这段代码:
#!/usr/bin/python
# Filename : hello.py
from sqlite3 import *
conn = connect('database')
c = conn.cursor()
c.execute('select * from table limit 2')
for row in c:
newname = row[1]
newname = newname[:-3]+"hello"
newdata = "UPDATE table SET name = '" + newname + "', originalPath = '' WHERE id = '" + str(row[0]) + "'"
print row
c.execute(newdata)
conn.commit()
c.close()
它就像第一行的魅力一样,但由于某种原因它只运行一次循环(只有表中的第一行被修改).当我删除“c.execute(newdata)”时,它会循环遍历表中的前两行,就像它应该的那样.我如何使其工作?
最佳答案 这样做是因为只要你执行c.execute(newdata),光标就不再指向原始结果集了.我会这样做:
#!/usr/bin/python
# Filename : hello.py
from sqlite3 import *
conn = connect('database')
c = conn.cursor()
c.execute('select * from table limit 2')
result = c.fetchall()
for row in result:
newname = row[1]
newname = newname[:-3]+"hello"
newdata = "UPDATE table SET name = '" + newname + "', originalPath = '' WHERE id = '" + str(row[0]) + "'"
print row
c.execute(newdata)
conn.commit()
c.close()
conn.close()