我正在尝试测试公司产品中的功能.我们的软件将发出如下SOAP请求：
请求标题
POST /testfunction.php HTTP/1.1
Accept: application/soap+xml, application/xml, text/xml
SOAPAction: "http://www.abc.com/testfunction#test"
Host: soap.abc.com
Content-Length: 461
Connection: Keep-Alive
请求内容
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://www.abc.com/testfunction">
<SOAP-ENV:Body>
<ns1:test>
<productID>3</productID>
<productSubID>1</productSubID>
<version>1.0.1</version>
<serialNumber/>
<language>EN</language>
<daysLicensed>0</daysLicensed>
<daysLeft>0</daysLeft>
</ns1:test>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
SOAP服务应该响应：
响应标题
HTTP/1.1 200 OK
Server: nginx/0.7.67
Date: Mon, 02 May 2011 13:43:46 GMT
Content-Type: text/xml; charset=utf-8
Connection: keep-alive
X-Powered-By: PHP/5.3.3-1ubuntu9.3
Content-Length: 304
Content-encoding: gzip
响应内容
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://www.abc.com/testfunction"><SOAP-ENV:Body><ns1:testResponse><result>1000</result></ns1:testResponse></SOAP-ENV:Body></SOAP-ENV:Envelope>
一开始我以为我可以在web.py中创建一个Web服务,并在有人在http://www.abc.com/testfunction发出POST请求时返回相同的响应.
import web
url = (
'/testfunction', 'testfunction',
)
class testfunction:
def POST(self):
web.header('Content-Type', 'text/xml; charset=utf-8')
return """<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://www.abc.com/testfunction"><SOAP-ENV:Body><ns1:testResponse><result>1000</result></ns1:testResponse></SOAP-ENV:Body></SOAP-ENV:Envelope>
"""
app = web.application(url, globals())
if __name__== "__main__":
app.run()
但它没有用.我想这可能与标题有关.然后我尝试使用SimpleXMLRPCServer.
from SimpleXMLRPCServer import SimpleXMLRPCServer, SimpleXMLRPCRequestHandler
import xmlrpclib
class MyRequestHandler(SimpleXMLRPCRequestHandler):
rpc_paths = ('/',)
def do_POST(self):
return SimpleXMLRPCRequestHandler.do_POST(self)
def test():
return "hello, world"
server = SimpleXMLRPCServer(
("0.0.0.0", 80),
requestHandler = MyRequestHandler,
)
server.register_function(test, 'test')
server.serve_forever()
但问题是我不知道如何在标题中处理SOAPAction,而客户端在这里没有使用测试函数.谁能帮我？非常感谢！！
更新：
终于做到了,使用以下代码：
from wsgiref.simple_server import WSGIServer, WSGIRequestHandler
def echo(environ, start_response):
status = "200 OK"
headers = [("Content-type", "text/xml")]
start_response(status, headers)
return ["""<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://www.abc.com/testfunction"><SOAP-ENV:Body><ns1:testResponse><result>1000</result></ns1:testResponse></SOAP-ENV:Body></SOAP-ENV:Envelope>"""]
httpd = WSGIServer(('0.0.0.0', 80), WSGIRequestHandler)
httpd.set_app(echo)
httpd.serve_forever()
它应该与web.py代码一样,但web.py没有.从wireshark中捕获的包中,我在xml内容之前和之后发现了一些乱码(“3bc”和“0”),与编码有关？
最佳答案 您可以使用
soaplib创建一个真正的SOAP服务,该服务实现您的接口并返回虚拟数据.这应该更容易维护,然后创建手写静态响应,并且代码不应该比基于web.py的示例更长.
