参见英文答案 >
How to test multiple variables against a value? 20个
original = raw_input('Enter a word:')
if len(original) > 0 and original.isalpha():
word = original.lower()
first = str(word)[0]
print first
if str(first) == "a" or "e" or "i" or "u" or "o":
print "vowel"
else:
print "consonant"
我想检查一个单词是否以元音或辅音开头.但是,这部分不起作用:如果str(first)==“a”或“e”或“i”或“u”或“o”
那么你如何检查第一个字母是“a”还是“e”或“i”或“u”还是“o”?
最佳答案 你最好用
if len(original) and original.isalpha():
word = original.lower()
first = word[0]
print first
if first in ('a','e','i','o','u'):
print "vowel"
else:
print "consonant"
你也做错了,如果你试图使用OR子句你必须使用这样但是它不是更好的pythonic方式:
if first =='a' or first =='e' or first =='i' or first =='o' or first =='u':