用于添加和删除列表中的值的代码是在不同线程中执行的操作.
在多线程中使用这些全局变量:
from threading import Thread
import time
a=[]
i = 0
j = 0
thread1的函数:
def val_in():
while 1:
a.append(raw_input())
print "%s value at %d: %d added" % ( time.ctime(time.time()), i ,int(a[i])) // line 14
i+=1
线程2的功能:
def val_out():
while 1:
time.sleep(5)
try:
print "%s value at %d: %d deleted" % (time.ctime(time.time()), j, int(a.pop(j)))
i-=1
except:
print"no values lefts"
time.sleep(2)
定义和启动线程:
t = Thread(target = val_in)
t1 = Thread(target= val_out)
t.start()
t1.start()
现在当输入为1时,它应该被添加到列表a中,但是有一个错误:
Error: Exception in thread Thread-1:
Traceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 810, in __bootstrap_inner
self.run()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 763, in run
self.__target(*self.__args, **self.__kwargs)
File "/Users/dhiraj.agarwal/Documents/workspace/try3/multithread.py", line 14, in val_in
UnboundLocalError: local variable 'i' referenced before assignment
最佳答案 你应该告诉python我是全局的:
def val_in():
global i
...
def val_out():
global i
...