我有这个代码:
<script>
$(document).ready(function()
{
refresh();
});
function refresh()
{
$.get('getMessageDetails.php', function (json) {
alert(json);
alert(json[0].subject);
},"json");
window.setTimeout(refresh,30000);
}
</script>
然后我有getMessageDetails.php:
<?php
//header('Content-Type: application/json; charset=utf-8');
include('header_application.php');
$lastNewMessageCnt = $obj_clean->getUnopenedMessagesCount($_SESSION['user_id']) + 1;
$last_unopened_message_row = $obj_clean->getLastUnopenedMessage($_SESSION['user_id'],$lastNewMessageCnt);
echo json_encode($last_unopened_message_row);
?>
然后我有警报(json),显示:
[{"subject":"Freechat ddd","id":"19","created_at":"2011-08-29 14:58:27","unique_code":"ALLEYCA000RC","opened_once":"0"}]
哪个是对的
但警告(json [0] .subject);给undefined ???
请帮忙?
谢谢
最佳答案 如果您的第一个警报显示您所说的内容,那么您的json变量的内容不会被视为json – 如果您在警报中看到[object Object].检查
here.
所以你需要指定返回的是json(你做的);但是你也应该确保PHP发送正确的响应头.在发送输出之前添加下面的第一行:
header('Content-type: application/json');
echo json_encode($last_unopened_message_row);