我有3张桌子.我想按item.name分组并计算在idetail中可以找到的次数.此查询仅计算不按行分组的所有行.
任何人都知道如何解决它?
SELECT i.name, COUNT(i.name)
FROM item AS i
INNER JOIN item_category AS ic ON i.i_category_id = ic.ic_id
INNER JOIN idetail AS id ON ic.ic_id = id.id_category_id
WHERE ic.ic_id = 1002
GROUP BY i.name
最佳答案 这就是你想要的:
select x.name
, count(*) as cntNames
, sum(x.cntDetails) as cntDetails
from (
SELECT i.name, COUNT(*) as cntDetails
FROM item AS i
INNER JOIN item_category AS ic ON i.i_category_id = ic.ic_id
INNER JOIN idetail AS id ON ic.ic_id = id.id_category_id
WHERE ic.ic_id = 1002
-- NOTICE THE 2nd Value in the group by!
GROUP BY i.name,id.id_category_id
) x
group by name