从另一个安装的应用程序,我有这样的模型
class Organization(model.Model):
name = models.CharField(max_length=255, blank=True)
class Person(model.Model):
name = models.CharField(max_length=255, blank=True)
class Membership(model.Model):
organization = models.ForeignKey(
Organization,
related_name='memberships',
# memberships will go away if the org does
on_delete=models.CASCADE,
help_text="A link to the Organization in which the Person is a member.")
person = models.ForeignKey(
Person,
related_name='memberships',
null=True,
# Membership will just unlink if the person goes away
on_delete=models.SET_NULL,
help_text="A link to the Person that is a member of the Organization.")
在我的应用程序中,我需要为某些模型添加一些方法.所以我有一个类似的模型
class ProxiedOrganization(other_app.models.Organization):
class Meta:
proxy = True
special_attribute = 'foo'
class ProxiedPerson(other_app.models.Person):
class Meta:
proxy = True
def special_method(self):
print('I do something special')
当我从组织获得成员资格时,它们的类型为other_app.models.Person.
> type(proxied_org_instance.memberships[0].person)
<class 'other_app.models.Person'>
但是,我希望它们是我的代理类的实例
> type(proxied_org_instance.memberships[0].person)
<class 'my_app.models.ProxiedPerson'>
有这样做的好方法吗?这是我可以用查询管理器做的事情吗?该解决方案必须适用于Django 2.0.
最佳答案 您需要将组织中的ForeignKey放入ProxiedPerson.例如:
class MemberShip(models.Model):
person = models.ForeignKey(
ProxyPerson,
related_name='memberships',
null=True,
# Membership will just unlink if the person goes away
on_delete=models.SET_NULL,
help_text="A link to the Person that is a member of the Organization.")
或者您可以通过以下方式获取代理人实例:
proxy_person = ProxyPerson.objects.get(pk=proxied_org_instance.memberships[0].person.pk)
要么
proxy_persons = ProxyPerson.objects.filter(
pk__in = proxied_org_instance.memberships.all().values_list('person_id')
)
The MyPerson class operates on the same database table as its parent
Person class. In particular, any new instances of Person will also be
accessible through MyPerson, and vice-versa
表示您可以通过ProxyPerson Instance访问Person Instance,反之亦然.