如何在cakephp 3中获得最近每小时/每日/每周/每年间隔的总计数总和？

2023年9月7日 81次阅读

我有一张桌子如下 –

《如何在cakephp 3中获得最近每小时/每日/每周/每年间隔的总计数总和？》

现在我需要报告每小时,每周,每月和每年的总计数.它可能有0,但应该包含在结果中.例如,我需要如下结果 –

$hourlyResult = array(
'00:01' => '5',
'00:02' => '9',
'00:03' => '50',
'00:04' => '5',
..............
..............
'00:55' => '95',
'00:56' => '0',
'00:57' => '20',
'00:58' => '33',
'00:59' => '5',
);

$weeklyResult = array(
'SAT' => '500',
'SUN' => '300'
.............
.............
'FRI' => '700'
);

如何在cakephp 3中构建查询？我得到以下链接,但不能到目前为止.

GROUP BY WEEK with SQL

我做了什么 –

    $this->loadModel('Searches');   
    $searches = $this->Searches
        ->find('all')
        ->select(['created', 'count'])
        ->where('DATE(Searches.created) = DATE_SUB(CURDATE(), INTERVAL 1 DAY)')
        ->group(WEEK(date))
        ->hydrate(false)
        ->toArray();
    pr($searches);

最佳答案 这是你如何做到的.

按年计算

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'year' => $query->func()->year(['created' => 'literal'])
        ])
        ->group(['year'])
        ->hydrate(false);

要么

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'year' => 'YEAR(created)'])
        ->group(['year'])
        ->hydrate(false);

按周计算

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'day_of_week' => $query->func()->dayOfWeek('created')
        ])
        ->group(['day_of_week'])
        ->hydrate(false);

要么

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'day_of_week' => 'DAYOFWEEK(created)'])
        ->group(['day_of_week'])
        ->hydrate(false);

以同样的方式获得按小时或月计的总和.
在这里你可以阅读约CakePHP > Using SQL Functions和date and time functions in MySQL.

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