我有三个数据库表.
CREATE TABLE `tblproject` (
`ProjectID` int(11) NOT NULL,
`ProjectStatusID` varchar(30) NOT NULL,
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
CREATE TABLE `tblSkills` (
`SkillID` int(11) NOT NULL,
`Skill` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
CREATE TABLE `tblprojectSkills` (
`ProjectSkillID` int(11) NOT NULL,
`ProjectID` int NOT NULL,
`SkillID` int NOT NULL,
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
在上表中. SkillID与tblSkills和tblprojectSkills相关.
ProjectID与Project和projectSkills表相关
我的项目模型如下.
class Project_Model extends Model
{
protected $table = "tblproject";
protected $primaryKey = "ProjectID";
public $timestamps = false;
public function ProjectSkills() {
return $this->hasMany('\App\Models\ProjectSkill_Model', 'ProjectID');
}
}
laravel 5.1中的数据库查询如下.
\App\Models\Project\Project_Model
::with('ProjectSkills')
->where('ProjectID', '=', $ProjectID)->first();
题
我可以获得技能ID,但是,我如何从技能表中获得技能名称?
最佳答案 您可以使用闭包选择所需的字段:
\App\Models\Project\Project_Model
::with('ProjectSkills' => function($q)
{
$q->select('SkillID', 'Skill');
})
->where('ProjectID', '=', $ProjectID)->first();
或者,您可以在模型的关系中直接添加所需的字段:
public function ProjectSkills() {
return $this->hasMany('\App\Models\ProjectSkill_Model', 'ProjectID')
->select('SkillID', 'Skill');
}