PHP在同一个键AND值上合并两个数组

2023年9月10日 195次阅读

我有两个数组.我想将它们合并到相同的键AND值上.如果它们具有相同的ur_user_id,则它们将被合并. array2只为array1提供了一些额外的数据,所以new_array.length = array1.length. array1只是从array2获取附加数据.

$array1 =    
    array(
        array('ur_user_id'=> 1,'ur_fname'=>'PerA','ur_lname'=>'SonA'),
        array('ur_user_id'=> 2,'ur_fname'=>'PerB','ur_lname'=>'SonB'),
        array('ur_user_id'=> 3,'ur_fname'=>'PerC','ur_lname'=>'SonC'),
    );
$array2 = 
    array(
        array('ur_user_id' => 5,'ur_code' => 'EE','ur_user_role' => 'testE'),
        array('ur_user_id' => 4,'ur_code' => 'DD','ur_user_role' => 'testD'),
        array('ur_user_id' => 6,'ur_code' => 'FF','ur_user_role' => 'testF'),
        array('ur_user_id' => 3,'ur_code' => 'CC','ur_user_role' => 'testC'),
        array('ur_user_id' => 1,'ur_code' => 'AA','ur_user_role' => 'testA'),
        array('ur_user_id' => 2,'ur_code' => 'BB','ur_user_role' => 'testB'),
    );

然后新数组必须如下所示.它将包含array1和array2中的值.

$new_array =    
    array(
        array('ur_user_id'=> 1,'ur_fname'=>'PerA','ur_lname'=>'SonA','ur_code' => 'AA','ur_user_role' => 'testA'),
        array('ur_user_id'=> 2,'ur_fname'=>'PerB','ur_lname'=>'SonB','ur_code' => 'BB','ur_user_role' => 'testB'),
        array('ur_user_id'=> 3,'ur_fname'=>'PerC','ur_lname'=>'SonC','ur_code' => 'CC','ur_user_role' => 'testC'),
    );

array1.length总是小于或等于array2.length永远不会更大.并且两个数组的顺序不会总是有序.我已经尝试了下面的函数,我在这里的某处,但它对我不起作用,我对循环不太好.

function merge_common_keys(){
    $arr = func_get_args();
    $num = func_num_args();

    $keys = array();
    $i = 0;
    for ($i=0; $i<$num; ++$i){
        $keys = array_merge($keys, array_keys($arr[$i]));
    }
    $keys = array_unique($keys);

    $merged = array();

    foreach ($keys as $key){
        $merged[$key] = array();
        for($i=0; $i<$num; ++$i){
            $merged[$key][] = isset($arr[$i][$key]) ? $arr[$i][$key] : null;
        }
    }
    return $merged;
}

基于给定的数组,结果是这样的.它只合并在同一个键上.

Array
(
    [0] => Array
        (
            [0] => Array
                (
                    [ur_user_id] => 1
                    [ur_fname] => PerA
                    [ur_lname] => SonA
                )

            [1] => Array
                (
                    [ur_user_id] => 5
                    [ur_code] => AA-BB-CC
                    [ur_user_role] => testE
                )

        )

最佳答案 试试这段代码,它可能对你有帮助,它很简短,没有遍历循环：

    usort($array2,function($a,$b){
        return strnatcmp($a['ur_user_id'],$b['ur_user_id']);
    });
    $array3 = array_replace_recursive($array1, $array2);

    $result = array_uintersect($array3,$array1,function($a,$b){
        return strnatcmp($a['ur_user_id'],$b['ur_user_id']);
    });
    print_r($result);

产量

Array
(
    [0] => Array
        (
            [ur_user_id] => 1
            [ur_fname] => PerA
            [ur_lname] => SonA
            [ur_code] => AA
            [ur_user_role] => testA
        )

    [1] => Array
        (
            [ur_user_id] => 2
            [ur_fname] => PerB
            [ur_lname] => SonB
            [ur_code] => BB
            [ur_user_role] => testB
        )

    [2] => Array
        (
            [ur_user_id] => 3
            [ur_fname] => PerC
            [ur_lname] => SonC
            [ur_code] => CC
            [ur_user_role] => testC
        )

)

这是Demo

点赞