c# – 转换为不包括表单成员的接口

2023年9月20日 185次阅读

我正在使用C#开发一个具有在表单上声明的接口的应用程序：

public partial class frmProjectForm : Form, IProjectInfo
{

}

public interface IProjectInfo
{
    string ProjectName { get; set; }
    string ProjectTitle { get; set; }
    string ProjectDescription { get; set; }
    string ProjectAuthor { get; set; }
    string ProjectCopyright { get; set; }
    string ProjectTrademark { get; set; }
    string ProjectCreationDate { get; set; }
    string ProjectVersion { get; set; }
    string ProjectFileName { get; }
    string ProjectFilePath { get; }
    string FullProjectPath { get; }
}

在应用程序的某个地方我想这样做：

frmProjectForm f = new frmProjectForm();
f.ShowDialog(this);
...
...
IProjectInfo getProjectInfoMembersOnly = (IProjectInfo)f;

// persist the IProjectInfo members to JSON
string project = JsonConvert.SerializeObject( getProjectInfoMembersOnly );

JsonConvert.SerializeObject方法正在爆炸并抱怨Button控件上的一些自引用循环.转换操作不排除表单,我不知道为什么因为我只希望接口转换只返回接口成员.

我究竟做错了什么？

最佳答案 对我来说,序列化代码可以处理对象的实际类型,而不是作为参数传递的类型(这甚至可能是函数接受对象类型的参数,而不是通用函数SerializeObject< T>(T obj)似乎是正常的. )).

如果你想要切割你的对象,我恐怕你必须自己执行切片,创建一个实现接口的对象并只复制其成员.

public class ProjectInfo : IProjectInfo
{
    public string ProjectName { get; set; }
    public string ProjectTitle { get; set; }
    public string ProjectDescription { get; set; }
    public string ProjectAuthor { get; set; }
    public string ProjectCopyright { get; set; }
    public string ProjectTrademark { get; set; }
    public string ProjectCreationDate { get; set; }
    public string ProjectVersion { get; set; }
    public string ProjectFileName { get; private set; }
    public string ProjectFilePath { get; private set; }
    public string FullProjectPath { get; private set; }

    public ProjectInfo(IProjectInfo src)
    {
        this.ProjectName = src.ProjectName;
        this.ProjectTitle = src.ProjectTitle;
        this.ProjectDescription = src.ProjectDescription;
        this.ProjectAuthor = src.ProjectAuthor;
        this.ProjectCopyright = src.ProjectCopyright;
        this.ProjectTrademark = src.ProjectTrademark;
        this.ProjectCreationDate = src.ProjectCreationDate;
        this.ProjectVersion = src.ProjectVersion;
        this.ProjectFileName = src.ProjectFileName;
        this.ProjectFilePath = src.ProjectFilePath;
        this.FullProjectPath = src.FullProjectPath;
    }
}

然后你可以这样使用它：

frmProjectForm f = new frmProjectForm();
f.ShowDialog(this);
...
...
IProjectInfo getProjectInfoMembersOnly = new ProjectInfo(f); //I only changed this line

// persist the IProjectInfo members to JSON
string project = JsonConvert.SerializeObject( getProjectInfoMembersOnly );
点赞