我想使用参数修改提交的symfony表单的url.从这个平台尝试了许多解决方案,没有一个解决方案有帮助!
当前网址如下:http:// localhost:8000 / search?app_bundle_search_form [search] = qui& app_bundle_search_form [brand] =& app_bundle_search_form [price] = 500,100000& app_bundle_search_form [_token] = BtA5bZb9HErUXzXFzGFbpEhlD6nD33zr7tKiPLxjpy4
我希望它像`http://localhost:8000/search?search=qui?brand=?minprice=500?maxprice=100000
这是我的控制器:
public function searchAction($searchTerm=null,Request $request)
{
if ($request->getMethod() == 'GET') {
$searchTerm = $request->query->get('app_bundle_search_form')['search'];
$searchBrand = $request->query->get('app_bundle_search_form')['brand'];
$price = $request->query->get('app_bundle_search_form')['price'];
$price = explode(",", $price);
$minPrice = $price[0];
$maxPrice = $price[1];
$em = $this->getDoctrine()->getManager();
$search = $em->getRepository('AppBundle:Classified')->searchClassifieds($searchTerm, $searchBrand, $minPrice, $maxPrice);
}
return $this->render('search-result.html.twig', [
'searchTerm' => $searchTerm,
'results' => $search
]);
}
形成:
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->setMethod('GET')
->add('search', TextType::class,array(
'required'=> false
))
->add('brand',EntityType::class,[
'class'=>Brand::class,
'placeholder'=>'Choose a brand',
'required'=>false,
'query_builder'=>function(BrandRepository $repo){
return $repo->DistinctBrandValue();
}
])
->add('price', TextType::class, array(
'required' => true,
'label' => 'Price',
'attr' => [
'data-slider-min' => '500',
'data-slider-max' => '100000',
'data-slider-step' => '2',
'data-slider-value' => "[500,100000]",
]))
;
}
路由
search:
path: /search
defaults:
_controller: AppBundle:Search:search
requirements:
methods: GET
枝条:
{{ form_start(search, { action: path('search')}) }}
{{ form_widget(search) }}
<button class="btn btn-outline-success my-2 my-sm-0" type="submit">{% trans %}Search{% endtrans %}</button>
<a href="{{ path('search') }}" class="btn btn-primary">{% trans %}Cancel{% endtrans %}</a>
{{ form_end(search) }}
提前致谢!
编辑:
所以我做的是我必须将表单名称设为null.
public function getBlockPrefix()
{
return '';
}
并将csrf保护设置为false.
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'csrf_protection' => false,
]);
}
并且还在控制器中将表单名称更改为null.现在网址看起来好一点!
最佳答案 您可以覆盖formType中的getName方法并返回一个空字符串,例如:
形成:
public function getName()
{
return '';
}
希望这有帮助