取石子游戏

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1911    Accepted Submission(s): 1094

Problem Description 1堆石子有n个,两人轮流取.先取者第1次可以取任意多个，但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍。取完者胜.先取者负输出”Second win”.先取者胜输出”First win”.  

Input 输入有多组.每组第1行是2<=n<2^31. n=0退出.  

Output 先取者负输出”Second win”. 先取者胜输出”First win”. 

参看Sample Output.  

Sample Input 2 13 10000 0  

Sample Output Second win Second win First win  

Source
ECJTU 2008 Autumn Contest  

Recommend lcy

模型介绍见世界冠军的博客：http://blog.csdn.net/acm_cxlove/article/details/7835016

#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
using namespace std;
int f[60];
int main()
{
    int n;
    f[0] = 1;
    f[1] = 1;
    for(int i = 2;i < 60;i++)
        f[i] = f[i-1]+f[i-2];
    while(scanf("%d",&n) == 1 && n)
    {
        bool flag = false;
        for(int i = 0;i <60;i++)
            if(n == f[i])
            {
                flag = true;
                break;
            }
        if(flag)printf("Second win\n");
        else printf("First win\n");
    }
    return 0;
}