B. Center Alignment

题目连接：

http://www.codeforces.com/contest/5/problem/B

Description

Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.

You are to implement the alignment in the shortest possible time. Good luck!

Input

The input file consists of one or more lines, each of the lines contains Latin letters, digits and/or spaces. The lines cannot start or end with a space. It is guaranteed that at least one of the lines has positive length. The length of each line and the total amount of the lines do not exceed 1000.

Output

Format the given text, aligning it center. Frame the whole text with characters «*» of the minimum size. If a line cannot be aligned perfectly (for example, the line has even length, while the width of the block is uneven), you should place such lines rounding down the distance to the left or to the right edge and bringing them closer left or right alternatively (you should start with bringing left). Study the sample tests carefully to understand the output format better.

Sample Input

This is

Codeforces
Beta
Round
5

Sample Output

• This is *

•      *

  Codeforces

• Beta *
• Round *

• 5    *

Hint

题意

给你一堆字符串，让你居中

如果恰好居中的话，那就居中

如果不是的话，先偏左边，然后再偏右边去

题解：

模拟题，按照题意模拟就好了。

代码

#include<bits/stdc++.h>
using namespace std;
const int maxn = 2005;
string s[maxn],s1;
int mx,tot;
int main()
{
    while(getline(cin,s1))
    {
        s[tot++]=s1;
        mx = max((int)s1.size(),mx);
    }
    for(int i=0;i<mx+2;i++)
        cout<<"*";
    cout<<endl;
    int d = 0;
    for(int i=0;i<tot;i++)
    {
        cout<<"*";
        int len = (mx-s[i].size());
        if(len%2==1)d++;
        int l = len/2;
        int r = len/2;
        if(len%2==1&&d%2==1)r++;
        else if(len%2==1)l++;
        for(int j=0;j<l;j++)cout<<" ";
        cout<<s[i];
        for(int j=0;j<r;j++)cout<<" ";
        cout<<"*"<<endl;
    }
    for(int i=0;i<mx+2;i++)
        cout<<"*";
    cout<<endl;
}