B. The Same Calendar

题目连接：

http://www.codeforces.com/contest/678/problem/B

Description

The girl Taylor has a beautiful calendar for the year y. In the calendar all days are given with their days of week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday.

The calendar is so beautiful that she wants to know what is the next year after y when the calendar will be exactly the same. Help Taylor to find that year.

Note that leap years has 366 days. The year is leap if it is divisible by 400 or it is divisible by 4, but not by 100 (https://en.wikipedia.org/wiki/Leap_year).

Input

The only line contains integer y (1000 ≤ y < 100’000) — the year of the calendar.

Output

Print the only integer y’ — the next year after y when the calendar will be the same. Note that you should find the first year after y with the same calendar.

Sample Input

2016

Sample Output

2044

Hint

题意

给你一个年y，让你找到大于y的某一年，使得和y这一年的日期一模一样。

题解：

其实就是经过的天数%7==0

而且那一年的平闰年和这一年是一样的。

代码

#include<bits/stdc++.h>
using namespace std;

bool check(int p)
{
    if(p%400==0)return 1;
    if(p%4==0&&p%100!=0)return 1;
    return 0;
}
int main()
{
    int y;
    scanf("%d",&y);
    int ans = y+1;
    int p=(365+check(ans))%7;
    while(p!=0||check(y)!=check(ans))
        p=(p+365+check(++ans))%7;
    cout<<ans<<endl;
}