#include<iostream>
using namespace std;
const int MaxLength = 3;
char c[10][10] = {"", "", "ABC", "DEF", "GHI", "JKL", "MNO", "PQRS", "TUV", "WXYZ"};
int total[10] = {0,0,3,3,3,3,3,4,3,4};
int number[MaxLength] = {2,3,4}; //本例输入数字2,3,4
int answer[MaxLength] = {0};
int len = 3;
//排列树问题
//fun1和递归的方法是相反的
void fun1()
{
while(true){
for(int i = 0; i < len; i++)
printf("%c", c[number[i]][answer[i]]);
printf("\n");
int k = len - 1;
while(k >= 0){
if(answer[k] < total[number[k]] - 1){
answer[k]++;
break;
}
else{
answer[k] = 0;
k--;
}
}
if(k < 0)
break;
}
}
//递归
void RecursiveSearch(int index,int n)
{
if(index==n)
{
for(int i=0;i<n;i++)
cout<<c[number[i]][answer[i]];
cout<<endl;
return;
}
for(answer[index]=0;answer[index]<total[number[index]];answer[index]++)
{
RecursiveSearch(index+1,n);
}
}
int main()
{
//RecursiveSearch(0,MaxLength);
fun1();
return 0;
}
编程之美3.2——电话号码对应英语单词
原文作者:kereus
原文地址: https://blog.csdn.net/arashif/article/details/45080779
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/arashif/article/details/45080779
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。