#include <iostream>
using namespace std;
template<typename Type>
struct Node
{
Node<Type> *right;
Node<Type> *left;
Type data;
Node(Type d = Type()) :data(d), right(NULL), left(NULL){}
};
template<typename Type>
class MyTree
{
public:
MyTree() :root(NULL)
{}
void Printf()
{
Printf(root);
}
void Create_tree_VL_(char *VLR,char *LVR)
{
int n = strlen(LVR);
_create_tree_VL_(root,VLR,LVR,n);
}
void Create_tree_LL_(char *LVR, char *LRV)
{
int n = strlen(LRV);
_create_tree_LL_(root, LVR, LRV, n);
}
private:
void _create_tree_LL_(Node<Type> *&t, char *LVR, char *LRV, int n)
{
if (n == 0)return;
int i = 0;
while (LRV[n - 1] != LVR[i])i++;
t = new Node<Type>(LRV[n-1]);
_create_tree_LL_(t->right,LVR+i+1,LRV+i,n-i-1);
_create_tree_LL_(t->left, LVR, LRV, i);
}
void _create_tree_VL_(Node<Type> *&t, char *VLR, char *LVR, int n)
{
if (n == 0)return;
int i = 0;
while (VLR[0] != LVR[i])i++;
t = new Node<Type>(VLR[0]);
_create_tree_VL_(t->left,VLR+1,LVR,i);
_create_tree_VL_(t->right, VLR + i + 1, LVR + i + 1, n - i - 1);
}
void Printf(Node<Type> *t)
{
if (t == NULL)return;
else
{
cout << t->data << " ";
Printf(t->left);
Printf(t->right);
}
}
private:
Node<Type> *root;
};
int main()
{
char VLR[] = "ABCDEFG";
char LVR[] = "CBDAFEG";
char LRV[] = "CDBFGEA";
//由前续及中序构造二叉树。
MyTree<char> mt;
mt.Create_tree_VL_(VLR,LVR);
mt.Printf();
cout << endl;
MyTree<char> my;
//由中序及后续构造二叉树。
my.Create_tree_LL_(LVR,LRV);
my.Printf();
return 0;
}
算法题:二叉树的构造
原文作者:让我们荡起双脚
原文地址: https://blog.csdn.net/liuhuiyan_2014/article/details/47338819
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
原文地址: https://blog.csdn.net/liuhuiyan_2014/article/details/47338819
本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。