Java 8 Stream.distinct() 列表去重示例

Java 8 Stream.distinct() 示例
 

    在这篇文章里,我们将提供Java8 Stream distinct()示例。 distinct()返回由该流的不同元素组成的流distinct()是Stream接口的方法。distinct()使用hashCode()和equals()方法来获取不同的元素。因此,我们的类必须实现hashCode()和equals()方法。如果distinct()正在处理有序流,那么对于重复元素,将保留以遭遇顺序首先出现的元素,并且以这种方式选择不同元素是稳定的。在无序流的情况下,不同元素的选择不一定是稳定的是可以改变的。distinct()执行有状态的中间操作。在有序流的并行流的情况下,保持distinct()的稳定性是需要很高的代价的,因为它需要大量的缓冲开销。如果我们不需要保持遭遇顺序的一致性,那么我们应该可以使用通过BaseStream.unordered()方法实现的无序流。

1. Stream.distinct()

distinct()方法的声明如下:

Stream<T> distinct()

它是Stream接口的方法。在此示例中,我们有一个包含重复元素的字符串数据类型列表

DistinctSimpleDemo.java

package com.concretepage;
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;
public class DistinctSimpleDemo {
    public static void main(String[] args) {
        List<String> list = Arrays.asList("AA", "BB", "CC", "BB", "CC", "AA", "AA");
        long l = list.stream().distinct().count();
        System.out.println("No. of distinct elements:"+l);
        String output = list.stream().distinct().collect(Collectors.joining(","));
        System.out.println(output);
    }
} 

Output
 

No. of distinct elements:3
AA,BB,CC 

2. Stream.distinct() with List of Objects

在此示例中,我们有一个Book对象列表。 为了对列表进行去重,该类将重写hashCode()和equals()。

Book.java

package com.concretepage;
public class Book {
    private String name;
    private int price;
    public Book(String name, int price) {
	this.name = name;
	this.price = price;
    }
    public String getName() {
	return name;
    }
    public int getPrice() {
	return price;
    }
    @Override
    public boolean equals(final Object obj) {
      if (obj == null) {
         return false;
      }
      final Book book = (Book) obj;
      if (this == book) {
         return true;
      } else {
         return (this.name.equals(book.name) && this.price == book.price);
      }
    }
    @Override
    public int hashCode() {
      int hashno = 7;
      hashno = 13 * hashno + (name == null ? 0 : name.hashCode());
      return hashno;
    }
} 

DistinctWithUserObjects.java

package com.concretepage;
import java.util.ArrayList;
import java.util.List;
public class DistinctWithUserObjects {
    public static void main(String[] args) {
        List<Book> list = new ArrayList<>();
        {
           list.add(new Book("Core Java", 200));
           list.add(new Book("Core Java", 200));
           list.add(new Book("Learning Freemarker", 150));        	
           list.add(new Book("Spring MVC", 300));
           list.add(new Book("Spring MVC", 300));
        }
        long l = list.stream().distinct().count();
        System.out.println("No. of distinct books:"+l);
        list.stream().distinct().forEach(b -> System.out.println(b.getName()+ "," + b.getPrice()));
    }
}

Output
 


No. of distinct books:3
Core Java,200
Learning Freemarker,150
Spring MVC,300 

3. Distinct by Property

distinct()不提供按照属性对对象列表进行去重的直接实现。它是基于hashCode()和equals()工作的。如果我们想要按照对象的属性,对对象列表进行去重,我们可以通过其它方法来实现。如下代码段所示:

static <T> Predicate<T> distinctByKey(Function<? super T, ?> keyExtractor) {
        Map<Object,Boolean> seen = new ConcurrentHashMap<>();
        return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
} 

上面的方法可以被Stream接口的 filter()接收为参数,如下所示:


list.stream().filter(distinctByKey(b -> b.getName())); 

distinctByKey()方法返回一个使用ConcurrentHashMap 来维护先前所见状态的 Predicate 实例,如下是一个完整的使用对象属性来进行去重的示例。

DistinctByProperty.java

package com.concretepage;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.concurrent.ConcurrentHashMap;
import java.util.function.Function;
import java.util.function.Predicate;
public class DistinctByProperty {
    public static void main(String[] args) {
        List<Book> list = new ArrayList<>();
        {
        	list.add(new Book("Core Java", 200));
        	list.add(new Book("Core Java", 300));
        	list.add(new Book("Learning Freemarker", 150));
        	list.add(new Book("Spring MVC", 200));
        	list.add(new Book("Hibernate", 300));
        }
        list.stream().filter(distinctByKey(b -> b.getName()))
              .forEach(b -> System.out.println(b.getName()+ "," + b.getPrice()));   
    }
    private static <T> Predicate<T> distinctByKey(Function<? super T, ?> keyExtractor) {
        Map<Object,Boolean> seen = new ConcurrentHashMap<>();
        return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
    }
} 

Output
 


Core Java,200
Learning Freemarker,150
Spring MVC,200
Hibernate,300 

from : 
https://www.concretepage.com/java/jdk-8/java-8-distinct-example

    原文作者:Haiyoung
    原文地址: https://blog.csdn.net/haiyoung/article/details/80934467
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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