# 3.13 计算最后一个周五的日期¶

## 解决方案¶

Python的 `datetime` 模块中有工具函数和类可以帮助你执行这样的计算。 下面是对类似这样的问题的一个通用解决方案：

```#!/usr/bin/env python
# -*- encoding: utf-8 -*-
"""
Topic: 最后的周五
Desc :
"""
from datetime import datetime, timedelta

weekdays = ['Monday', 'Tuesday', 'Wednesday', 'Thursday',
'Friday', 'Saturday', 'Sunday']

def get_previous_byday(dayname, start_date=None):
if start_date is None:
start_date = datetime.today()
day_num = start_date.weekday()
day_num_target = weekdays.index(dayname)
days_ago = (7 + day_num - day_num_target) % 7
if days_ago == 0:
days_ago = 7
target_date = start_date - timedelta(days=days_ago)
return target_date
```

```>>> datetime.today() # For reference
datetime.datetime(2012, 8, 28, 22, 4, 30, 263076)
>>> get_previous_byday('Monday')
datetime.datetime(2012, 8, 27, 22, 3, 57, 29045)
>>> get_previous_byday('Tuesday') # Previous week, not today
datetime.datetime(2012, 8, 21, 22, 4, 12, 629771)
>>> get_previous_byday('Friday')
datetime.datetime(2012, 8, 24, 22, 5, 9, 911393)
>>>
```

```>>> get_previous_byday('Sunday', datetime(2012, 12, 21))
datetime.datetime(2012, 12, 16, 0, 0)
>>>
```

## 讨论¶

```>>> from datetime import datetime
>>> from dateutil.relativedelta import relativedelta
>>> from dateutil.rrule import *
>>> d = datetime.now()
>>> print(d)
2012-12-23 16:31:52.718111

>>> # Next Friday
>>> print(d + relativedelta(weekday=FR))
2012-12-28 16:31:52.718111
>>>

>>> # Last Friday
>>> print(d + relativedelta(weekday=FR(-1)))
2012-12-21 16:31:52.718111
>>>
```