算法篇---银行家算法

银行家算法是一种最有代表性的避免死锁的算法。在避免死锁方法中允许进程动态地申请资源,但系统在进行资源分配之前,应先计算此次分配资源的安全性,若分配不会导致系统进入不安全状态,则分配,否则等待。

package com.zc.manythread;
import javax.swing.JOptionPane;
/*一共有5个进程需要请求资源,有3类资源*/
public class Bank {
    // 每个进程所需要的最大资源数
    public static int MAX[][] = { { 7, 5, 3 }, { 3, 2, 2 }, { 9, 0, 2 },
            { 2, 2, 2 }, { 4, 3, 3 } };
    // 系统拥有的初始资源数
    public static int AVAILABLE[] = { 10, 5, 7 };
    // 系统已给每个进程分配的资源数
    public static int ALLOCATION[][] = { { 0, 0, 0 }, { 0, 0, 0 }, { 0, 0, 0 },
            { 0, 0, 0 }, { 0, 0, 0 } };
    // 每个进程还需要的资源数
    public static int NEED[][] = { { 7, 5, 3 }, { 3, 2, 2 }, { 9, 0, 2 },
            { 2, 2, 2 }, { 4, 3, 3 } };
    // 每次申请的资源数
    public static int Request[] = { 0, 0, 0 };
    // 进程数与资源数
    public static int M = 5, N = 3;
    int FALSE = 0;
    int TRUE = 1;
    public void showdata() {
        int i, j;
        System.out.print("系统可用的资源数为:/n");
        for (j = 0; j < N; j++) {
            System.out.print("资源" + j + ":" + AVAILABLE[j] + " ");
        }
        System.out.println();
        System.out.println("各进程还需要的资源量:");
        for (i = 0; i < M; i++) {
            System.out.print("进程" + i + ":");
            for (j = 0; j < N; j++) {
                System.out.print("资源" + j + ":" + NEED[i][j] + " ");
            }
            System.out.print("/n");
        }
        System.out.print("各进程已经得到的资源量: /n");
        for (i = 0; i < M; i++) {
            System.out.print("进程");
            System.out.print(i);
            for (j = 0; j < N; j++) {
                System.out.print("资源" + j + ":" + ALLOCATION[i][j] + " ");
            }
            System.out.print("/n");
        }
    }
    // 分配资源,并重新更新各种状态
    public void changdata(int k) {
        int j;
        for (j = 0; j < N; j++) {
            AVAILABLE[j] = AVAILABLE[j] - Request[j];
            ALLOCATION[k][j] = ALLOCATION[k][j] + Request[j];
            NEED[k][j] = NEED[k][j] - Request[j];
        }
    };
    // 回收资源,并重新更新各种状态
    public void rstordata(int k) {
        int j;
        for (j = 0; j < N; j++) {
            AVAILABLE[j] = AVAILABLE[j] + Request[j];
            ALLOCATION[k][j] = ALLOCATION[k][j] - Request[j];
            NEED[k][j] = NEED[k][j] + Request[j];
        }
    };
    // 释放资源
    public void free(int k) {
        for (int j = 0; j < N; j++) {
            AVAILABLE[j] = AVAILABLE[j] + ALLOCATION[k][j];
            System.out.print("释放" + k + "号进程的" + j + "资源!/n");
        }
    }
    public int check0(int k) {
        int j, n = 0;
        for (j = 0; j < N; j++) {
            if (NEED[k][j] == 0)
                n++;
        }
        if (n == 3)
            return 1;
        else
            return 0;
    }
    // 检查安全性函数
    public int chkerr(int s) {
        int WORK;
        int FINISH[] = new int[M], temp[] = new int[M];// 保存临时的安全进程序列
        int i, j, k = 0;
        for (i = 0; i < M; i++)
            FINISH[i] = FALSE;
        for (j = 0; j < N; j++) {
            WORK = AVAILABLE[j]; // 第j个资源可用数
            i = s;
            // 判断第i个进程是否满足条件
            while (i < M) {
                if (FINISH[i] == FALSE && NEED[i][j] <= WORK) {
                    WORK = WORK + ALLOCATION[i][j];
                    FINISH[i] = TRUE;
                    temp[k] = i;
                    k++;
                    i = 0;
                } else {
                    i++;
                }
            }
            for (i = 0; i < M; i++)
                if (FINISH[i] == FALSE) {
                    System.out.print("/n系统不安全!!! 本次资源申请不成功!/n");
                    return 1;
                }
        }
        System.out.print("/n经安全性检查,系统安全,本次分配成功。/n");
        System.out.print("本次安全序列:");
        for (i = 0; i < M - 1; i++) {
            System.out.print("进程" + temp[i] + "->");
        }
        System.out.print("进程" + temp[M - 1]);
        System.out.println("/n");
        return 0;
    }
    /**
     * @param args
     */
    public static void main(String[] args) {
        int i = 0, j = 0;
        int flag = 1;
        Bank bank = new Bank();
        bank.showdata();
        while (flag == 1) {
            i = -1;
            while (i < 0 || i >= M) {
                String str = JOptionPane.showInputDialog("请输入需申请资源的进程号(从0到"
                        + (M - 1) + ",否则重输入!)");
                i = Integer.parseInt(str);
                if (i < 0 || i >= M)
                    System.out.println("输入的进程号不存在,重新输入!/n");
            }
            System.out.print("请输入进程" + i + "申请的资源数/n");
            for (j = 0; j < N; j++) {
                String str = JOptionPane.showInputDialog("资源" + j + ":");
                Request[j] = Integer.parseInt(str);
                if (Request[j] > NEED[i][j]) {
                    System.out.print("进程" + i + "申请的资源数大于进程" + i + "还需要" + j
                            + "类资源的资源量!申请不合理,出错!请重新选择!/n");
                    flag = 0;
                    break;
                } else {
                    if (Request[j] > AVAILABLE[j]) {
                        System.out.print("进程" + i + "申请的资源数大于系统可用" + j
                                + "类资源的资源量!申请不合理,出错!请重新选择!/n");
                        flag = 0;
                        break;
                    }
                }
            }
            if (flag == 1) {
                bank.changdata(i);
                int chkerr = bank.chkerr(i);
                if (chkerr == 1) {
                    bank.rstordata(i);
                    bank.showdata();
                } else {
                    bank.showdata();
                    int check = bank.check0(i);
                    if (check == 1) {
                        System.out.print("进程" + i + "已经完成,系统将其所占用资源释放/n");
                        bank.free(i);
                    }                    
                }
            } else {
                bank.showdata();
            }
            System.out.println("/n");
            String str = JOptionPane
                    .showInputDialog("是否继续银行家算法演示,按'1'键继续,按'0'键退出演示");
            flag = Integer.parseInt(str);
        }
    }
}

《算法篇---银行家算法》

    原文作者:偶my耶
    原文地址: https://www.cnblogs.com/oumyye/p/4209368.html
    本文转自网络文章,转载此文章仅为分享知识,如有侵权,请联系博主进行删除。
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