(算法)整数转英文描述

题目:

给定一个整数,打印该整数的英文描述。(例如:“One Thousand, Two Hundred Thirty Four”)

思路:

每三位转换一次,在适当位置插入million,thousand。即:

convert(19 323 984)=convert(19)+” million, “+convert(323)+” thousand “+convert(984)

代码:

#include<iostream>
using namespace std;

string digits[]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
string teens[]={"Eleven","Twelve","ThirTteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
string tens[]={"Ten","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety"};
string bigs[]={"","Thousand,","Million,"};

string numToEnglish100(int num);

string numToEnglish(int num){
    if(num==0)
        return "Zero";
    else if(num<0){
        return "Negative " + numToEnglish(-1*num);
    }

    int count=0;
    string str="";

    while(num>0){
        if(num%1000!=0){
            str=numToEnglish100(num%1000)+bigs[count]+" "+str;
        }
        num/=1000;
        count++;
    }

    return str;
}

string numToEnglish100(int num){
    string str="";
    if(num>=100){
        str+=digits[num/100-1]+" Hundred ";
        num%=100;
    }

    if(num>=11 && num<=19){
        return str+teens[num-11]+" ";
    }
    else if(num==10 || num>=20){
        str+=tens[num/10-1]+" ";
        num%=10;
    }

    if(num>=1 && num<=9)
        str+=digits[num-1]+" ";

    return str;
}

int main(){
    int num;
    while(cin>>num){
        cout<< numToEnglish(num) <<endl;
    }
    return 0;
}

 

    原文作者:AndyJee
    原文地址: https://www.cnblogs.com/AndyJee/p/4899198.html
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