题目描述:
有两个日期,求两个日期之间的天数,如果两个日期是连续的我们规定他们之间的天数为两天。
输入
有多组数据,每组数据有两行,分别表示两个日期,形式为YYYYMMDD
输出
每组数据输出一行,即日期差值
样例输入
20130101
20130105
样例输出
5
代码
#include<cstdio>
bool isLeap(int year){
return (year%4==0&&year%100!=0)||(year%400==0);
}
int main(){
int time1,y1,m1,d1;
int time2,y2,m2,d2;
int temp,ans=1;
int month[13][2]={{0,0},{31,31},{28,29},{31,31},{30,30},{31,31},{30,30},{31,31},{31,31},{30,30},{31,31},{30,30},{31,31}};
while(scanf("%d%d",&time1,&time2)!=EOF){
if(time1>time2){
temp=time1;
time1=time2;
time2=temp;
}
y1=time1/10000,m1=time1%10000/100,d1=time1%100;
y2=time2/10000,m2=time2%10000/100,d2=time2%100;
while(y1<y2||m1<m2||d1<d2){ //time1!=time2一直循环
d1++;
if(d1==month[m1][isLeap(y1)]+1){ //满当月天数
m1++;
d1=1;
}
if(m1==13){ //月份满12个月,月变成下一年的1月
y1++;
//当y1走完当年的天数,我们可以进行大跨步,跨至y1=y2-1;
while(y1<y2){
if(isLeap(y1))ans+=366;
else ans+=365;
y1++;
}
m1=1;
}
ans++;
}
printf("%d\n",ans);
ans=1;
}
return 0;
}