字符串搜索(1)

《字符串搜索(1)》

char *find_char(char const*source, char const *chars)
{
	for (; *source != '\0';)
	{
		char *temp = (char *)chars;

		for (; *temp != '\0';)
		{
			if (*source == *temp)
			{
				return (char *)source;
			}
			*temp++;
		}
		*source++;
	}
}


int _tmain(int argc, _TCHAR* argv[])
{
	cout << find_char("ABCDEF", "GDK") << endl;
	system("pause");
	return 0;
}

结果:

《字符串搜索(1)》

点赞