我有一些工作代码,我改变了,但我似乎无法得到小时变量的数学.我想假期我需要很多食物,因为我想要一个空白.
## {{{ http://code.activestate.com/recipes/124894/ (r2)
from Tkinter import *
import time
import pygtk
import gtk
import time
class StopWatch(Frame):
""" Implements a stop watch frame widget. """
def __init__(self, parent=None, **kw):
Frame.__init__(self, parent, kw)
self._start = 0.0
self._elapsedtime = 0.0
self._running = 0
self.timestr = StringVar()
self.makeWidgets()
def makeWidgets(self):
""" Make the time label. """
l = Label(self, textvariable=self.timestr)
self._setTime(self._elapsedtime)
l.pack(fill=X, expand=NO, pady=2, padx=2)
def _update(self):
""" Update the label with elapsed time. """
self._elapsedtime = time.time() - self._start
self._setTime(self._elapsedtime)
self._timer = self.after(50, self._update)
def _setTime(self, elap):
""" Set the time string to Minutes:Seconds:Hundreths """
hours = int(elap) #cant remember formula
minutes = int(elap/60)
seconds = int(elap - minutes*60.0)
hseconds = int((elap - minutes*60.0 - seconds)*100)
sn = time.strftime('%m/%d/%Y-%H:%M:%S')
self.timestr.set('%02s\n\n%02dh:%02dm:%02ds:%02d' % (sn,hours,minutes, seconds, hseconds))
def Start(self):
""" Start the stopwatch, ignore if running. """
if not self._running:
self._start = time.time() - self._elapsedtime
self._update()
self._running = 1
def Stop(self):
""" Stop the stopwatch, ignore if stopped. """
if self._running:
self.after_cancel(self._timer)
self._elapsedtime = time.time() - self._start
self._setTime(self._elapsedtime)
self._running = 0
def Reset(self):
""" Reset the stopwatch. """
self._start = time.time()
self._elapsedtime = 0.0
self._setTime(self._elapsedtime)
def main():
root = Tk()
root.title( "Stop Watch" )
sw = StopWatch(root)
sw.pack(side=TOP)
Button(root, text='Start', command=sw.Start).pack(side=LEFT)
Button(root, text='Stop', command=sw.Stop).pack(side=LEFT)
Button(root, text='Reset', command=sw.Reset).pack(side=LEFT)
Button(root, text='Quit', command=root.quit).pack(side=LEFT)
root.mainloop()
if __name__ == '__main__':
main()
## end of http://code.activestate.com/recipes/124894/ }}}
最佳答案 我从方程式推断出elap是以秒为单位测量的.由于您将小时数提取到单独的变量中,因此需要从分钟计数中删除它们.当然,由于分钟的含义与原始代码有所不同,因此您需要在计算的其余部分中遵循此操作.
hours = int(elap/3600)
minutes = int((elap-hours*3600)/60)
seconds = int(elap-hours*3600-minutes*60)
hseconds = int((elap-hours*3600-minutes*60-seconds)*100)
我想如果我写这篇文章,我会修改elap,因为我一直在努力减少重复.
hours = int(elap/3600)
elap -= hours*3600
minutes = int(elap/60)
elap -= minutes*60
seconds = int(elap)
elap -= seconds
hseconds = int(elap*100)
这样做可以更容易地看到正在发生的事情,并且将来也更容易修改.例如,如果您想在混合中添加天数,那么您需要做的就是将其移植到代码的开头:
days = int(elap/86400)
elap -= days*86400
现在,我在这里编写了代码,假设elap是一个浮点数,当然它在你的程序中.如果你特别偏执,你会在执行算术之前编写elap = float(elap).
但我同意@soulcheck认为使用库函数更清晰.